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IceJOKER [234]
3 years ago
7

Does anyone know this answer​

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

0 is the answer of questions

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SAT math scores have a bell-shaped distribution with a mean of 515 and a standard deviation of 114.
nadezda [96]

Hey there mate :)

Analysis :

401 = 515 - 114 = u - 6

And

173 = 515 - 3.114 = u - 36

=  \frac{p(u - 36 < u < u + 36) - p(u - 6 < u < u + 6)}{2}

=  \frac{99.73percent - 68.21percent}{2}

=  \frac{31.46percent}{2}

= {15.73percent}

Then, calculating,

u - 26 = 515 - 2 \times 114 = 287

And

u + 26 = 515 + 2 \times 114 = 743

Then,

The \: Range = (287,743)

Final Answers :-

<u>1</u><u>5</u><u>.</u><u>7</u><u>3</u><u> </u><u>%</u>

<u>(</u><u>2</u><u>8</u><u>7</u><u>,</u><u>7</u><u>4</u><u>3</u><u>)</u>

~Benjemin360

3 0
3 years ago
Write a real-world situation that could be modeled by the equation 500 + 250x = 300x
andre [41]
Jjxiejwijsncjdjjeje wjdjisnznakka
8 0
3 years ago
PLZ NEED HELP ASAP!!!
madam [21]

Answer:

C and D

Step-by-step explanation:

I had this same problem on my quiz

4 0
3 years ago
Given the function h(x) = 3(5)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.
otez555 [7]

We can write the function in terms of y rather than h(x) so that:

y = 3 (5)^x

 

A. The rate of change is simply calculated as:

r = (y2 – y1) / (x2 – x1) where r stands for rate

 

Section A:

rA = [3 (5)^1 – 3 (5)^0] / (1 – 0)

rA = 12

 

Section B:

rB = [3 (5)^3 – 3 (5)^2] / (3 – 2)

rB = 300

 

B. We take the ratio of rB / rA:

rB/rA = 300 / 12

rB/rA = 25

 

So we see that the rate of change of section B is 25 times greater than A

7 0
3 years ago
Help Asap Please!! mark as Brainliest
nekit [7.7K]

1. \frac{1}{2}(10m - 14) + 9 = 12        1. Given

2.    5m - 7 + 9 = 12          2. Distributive Property

3.    5m      + 2 = 12          3. Simplify (added like terms)

4.    5m            = 10          4. Subtraction Property of Equality

5.      m            =  2           5. Division Property of Equality


3 0
3 years ago
Read 2 more answers
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