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Delicious77 [7]
3 years ago
6

Two cross roads ,each width 10m cut at right angle through the centre of a rectangular park of length 700m and breadth 300m and

parallel to it's sides find the area of the roads .Also find the area of the park excluding cross roads .Give the answer in hectares
Mathematics
1 answer:
Dafna11 [192]3 years ago
7 0

Answer:

Step-by-step explanation:

Area of one  road = 700 x 10

7000 sq m

area of another road

= 300 x 10 = 3000sq m

Total area of road

= 7000 + 3000 - 10 x 10

= 9900 sq m

Area of park

= 700 x 300

= 210000 sq m

less area of road

= 210000 - 9900

= 200100 sq m

= 200100 / 10000 hectare

= 20.01 hectare.

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Solve this system of equations: y = 7; y = -2x+1 *
Gnoma [55]

Answer:

x = -3

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Step-by-step explanation:

y = -2x + 1

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6 0
3 years ago
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g (15 points) Suppose 42 out of 600 rats exposed to a potential carcinogen develop tumors. A control group of 350 rats not expos
vazorg [7]

Answer:

a) The relative risk is 1.8\overline{846153}

b) The attributable risk is 0.69 \overline{047619}

c) There is a relationship between exposure and tumor risk

Step-by-step explanation:

The number of exposed rats that develop tumors, a = 42

The number of rats exposed to the carcinogen = 600 rats

The number of exposed rats that did not develop tumors, b = 600 - 42 = 558

The number of not exposed rats in the control group = 350 rats

The number of rats that develop tumors in the control group, c = 13 tumors

The number of not exposed rats that did not develop tumors, d = 350 - 13 = 337  rats

a) The relative risk, RR = a/(a + b)/(c/(c + d))

∴ RR = (42/(42 + 558))/(13/(13 + 337)) = 49/26 = 1.8\overline{846153}

b) The attributable risk = (a - c)/a

∴ The attributable risk = (42 - 13)/42 = 0.69 \overline{047619}

c) The odds ratio = (a·b)/(c·d)

∴ The odds ratio = 42 × 558/(13 × 337) = 23439/4381 ≈ 5.35

Given that the result of attributable risk is positive, there is an indication that there is a higher probability to develop tumor when exposed to the potential carcinogen, therefore, there is a relationship between exposure and tumor risk

7 0
3 years ago
Show that cos2x=cosx
PSYCHO15rus [73]

cos (2x) = cos x

2 cos^2 x -1 = cos x   using the double angle formula

2 cos ^2 x -cos x -1 =0

factor

(2 cos x+1) ( cos x -1) = 0

using the zero product property

2 cos x+1 =0    cos x -1 =0

2 cos x = -1       cos x =1

cos x = -1/2       cos x=1

taking the arccos of each side

arccos cos x = arccos (-1/2)         arccos cos x = arccos 1

x = 120 degrees   x=-120   degrees           x=0

remember you get 2 values ( 2nd and 3rd quadrant)

these are the principal values

now we need to add 360

x = 120+ 360n      x=-120+ 360n      x = 0 + 360n  where n is an integer


3 0
3 years ago
Can someone help me please.
zhannawk [14.2K]

Answer:

  1. Lena's Method: 280
  2. Jackson's Method: 280

Step-by-step explanation:

Lena's Method:

  1. 8 + 12 = 20
  2. Plug 20 in: 14(20)
  3. 14(20) = 14 × 20 = 280

Jackson's Method:

  1. 14 × 8 = 112
  2. 14 × 12 = 168
  3. Re-write the expression: 112 + 168
  4. 112 + 168 = 280

I hope this helps!

8 0
3 years ago
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