X = 6
<span>6+8x/2 = 30 if x = 6 and 5x = 30 if x =6</span>
Answer:
-15
Step-by-step explanation:
go to the picture okay
Answer:
Step-by-step explanation:
as long as a and b are just numbers they can have infinitely many solutions. Basically, take any number, you can multiply it by some other number and in return get another number you choose. so if I want to multiply 3 by something to get literally any other number, I could. The simplest way is to multiply by the real number n/3 where n s that number we want to get to. Same if you add a b, you will just have to take that into account. So we want ax + b to equal a number n? make x be the number (n-b)/a You just have to pick a number for a, b and n.
equations with just an x are known as linear, because theya re just a straight line. maybe at an angle, but a straight line. a quadratic is a "degree" above, which means it has an x^2. Nothing higher, but it has to have an x^2. It can have a plain old x as well. so it is of the form ax^2 or ax^2 + bx or ax^2 + bx + c or even ax^2 + c. needs that x^2 as the highest exponent a variable has. also a cannot be 0 otherwise there won't be an x^2 and it'll just be linear again.
In relation to linear it is no longer straight, instead it has a single curve to it. after x^2 they can have more than one curve, so for instance a "degree three" equation could have up to two curves. degree three means the highest exponent on a variable is 3. but it could also have just one as well, and this pattern continues.
So to summarize, the relation between linear and quadratic is the degree of the variable being a difference of 1 which in turn means a difference of one "curve"
Answer:
ooooh he cheatingg
Step-by-step explanation:
answer is on the paper isnt it lool?
Answer: They are not congruent.
Step-by-step explanation:
You need to find the distance between these points to find congruence. If just one of these doesn't match with its corresponding side, its not congruent.
DE: square root of 68
_
GH: square root of 53
DE and GH are corresponding, but they are not congruent so these polygons are not congruent.
