Answer: Option (b) is the correct answer.
Explanation:
Kinetic energy is the energy of an object or particle when it is in motion.
Mathematically, Kinetic energy = 
It is given that toy truck has mass = 0.75 kg, and velocity = 4 m/s.
Calculate the kinetic energy as follows.
Kinetic energy =
= 
= 
= 
= 
or, Kinetic energy = 6 joules
Thus, we can conclude that kinetic energy of toy truck is 6 J.
Given data:
Yan speed;
Christopher speed;
Christophe starts 30 s later than Yan. Therefore, Christophe takes 30 s less than Yan to reach the same distance.
Part (A)
The distance is given as,
Let both Yan and Christophe meet at d distance from the start position. Therefore,
Substituting all known values,
Therefore, 600 s after Yan's departure Christophe will join him.
Part (B)
The distance is given as,
Substituting all known values,
Therefore, Christophe joins Yan after 6.17 km from the start.
(C). Remember gravity provides an acceleration of 9.81m/s^2, so the y component of velocity initial is zero because it isn’t already falling, and we have the height, so basically we use the kinematic equation vf^2=vi^2+2ad, substitute given values and you get vf^2=2(9.81)(65) which is 1275, when you take the square root you get 35.7m/s for final velocity
(B). Then you use vf=vi+at to get the equation 35.7=(9.81)t, when you divide out you get 3.64s for time t
(A). Finally, since we assume that there is no acceleration or deceleration horizonatally, we just multiply the time taken for it to hit the ground and the initial speed ((3.64)(35.7)) to get 129.96, with significant figures I would round that to 130 metres.
**this is in the order that I felt was easiest to answer**
Answer:
0.15A
Explanation:
The parameters given are;
R=20.0 Ω
C= 2.50 μF
V= 3.00 V
f= 2.48×10^-3 Hz
Xc= 1/2πFc
Xc= 1/2×3.142 × 2.48×10^-3 × 2.5 ×10^-6
Xc= 25666824.1
Z= 1/√(1/R)^2 +(1/Xc)^2
Z= 1/√[(1/20)^2 +(1/25666824.1)^2]
Z= 1/√(2.5×10^-3) + (1.5×10^-15)
Z= 20 Ω
But
V=IZ
Where;
V= voltage
I= current
Z= impedance
I= V/Z
I= 3.00/20
I= 0.15A
i belive the answe is c and if im wrong im tarrably sorry
