The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?
Answer:
Length(L)=22 inches
Width(W) = 7 inches
Step-by-step explanation:
GIven:-
Perimeter (p)=58 inches,
Length(L)= one more than 3 times the width(W)
Let, W=x ---------------------------------(equation 1
-----------------------(equation 2)
Here x is unknown and to find the Width(W) we have to find the value of x.
Now,
Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)

----------------(from equation 1)
----------------(given p=58 inches)




----------------------(equation 3)
Now substituting the value of equation 3 in equation 2.





as,
-----------------------(from equation 1)
inches -------------------(equation 3)
Therefore, Length(L) = 22 inches and Width(W) = 7 inches.
Answer: The answer is x = -10
Answer: first one 5.55
Step-by-step explanation:
-4x+8=42
-4x+8-8=42-8
-4x=34
-4x=34
-4x/-4=34/-4
x= - 17/3
Answer is 175
To start you need to work backwards from the mean so do 158*4 to give you the total of the revenue then simply minus what was given to get 175
Hope this helped