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4 years ago

Create equations to solve for missing angles may be hard for me to solve. Need help on this!!

Mathematics

1 answer:

Sonja [21]4 years ago

5 0

Answer: A.2x+30=90

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6. Five years ago, Ross was N times as old as

Tema [17]

Answer:

14N+5

Step-by-step explanation:

Five years ago; Rose Nx

Amanda x

Now; Rose Nx+5

Amanda x+5=19

x=19-5=14years

Rose(NOW) =14N+5

8 0

2 years ago

I forgot how to do this!! i'd like help please!!

user100 [1]

Answer:

9) 28

10) 22

Step-by-step explanation:

collinear means on the same line

9 ) AB+BC=AC

16+12=28

10) 13+9=22

3 0

3 years ago

In a class of c children there are 16 boys what fraction of the class are boys

ZanzabumX [31]

Answer:

Step-by-step explanation:

c/16

8 0

3 years ago

Help me please..........

romanna [79]

Answer: <em>(-3; -11)</em>

Step-by-step explanation:

$\left \bigg \{ {\big{y=7x+10} \atop\big {y=-4x-23}} \right.\\\\7x+10=-4x-23\\7x+10-10=-4x-23-10\\7x=-4x-33\\7x+4x=-4x-33+4x\\11x=-33\\11x \div 11=-33 \div 11\\x=-3\\\\y=7x+10\\y=7 \times (-3)+10=-21+10=-11$

5 0

3 years ago

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

8 0

4 years ago

Create equations to solve for missing angles may be hard for me to solve. Need help on this!!​

Create equations to solve for missing angles may be hard for me to solve. Need help on this!!