Answer:
Step-by-step explanation:
Method
The smallest the third side can be is something just larger than 2
You get 2 by subtracting10 and 8. The third side is just a bit larger. 8 and 2 will make up the length of 10 so you cannot use 2 itself
The largest value possible is just under 18. You get 18 by adding 8 and 10 together. So to get a triangle, you need just under 18.
Answer
2<s<18
A
Answer:
Step-by-step explanation:
3*(2k + 3) - 8k + 5 + 5 Remove the brackets on the left
6k + 9 - 8k + 5 + 5 Combine like terms
6k-8k+9 + 5 + 5
-2k + 19
Answer:
4
Step-by-step explanation:
a) x/2 + 4y
= 10/2 + 4*2 = 5 + 8 = 13
b) 3 (p + 2q)
= 3 (8 + 2*3) = 3 (8 + 6 ) = 3* 14 = 42
c) m + n ( q + 3)
= 4.5 + 6 (-1 + 3) = 10.5 * 2 = 21
d) (u+v)^x
= (7 + (-4) ) ^ 4 = (7-4)^4 = 3^4 = 81
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Let a be the number of adults which bought a ticket and c the number of children who bought a ticket. We can use the information given to assemble a system of equations.
Tickets cost 8 dollars for a, 1 dollar for c, and the total amount made is 100
8a + c = 100
The total of a and c is 30
a + c = 30
We can now subtract one equation from the other to use the elimination method to solve the system.
8a + c = 100
-(a + c = 30)
7a + 0 = 70
We can now solve for a.
7a = 70
a = 10
There were 10 adults who bought tickets. We can use this value as a known, plugging it into an equation to solve for the number of children.
a + c = 30
10 + c = 30
c = 20
So, the final answer is "20 children and 10 adults Equation 1: a + c = 30 Equation 2: 8a + c = 100".
