Question

100 Points!! Pls answer ASAP, short explanation as well. Thx!

Answer 1

Answer:

2/3 x $\sqrt[4]{y^2}$

Step-by-step explanation:

( 16 x^11 y^8 / 81 x^7 y^6) ^ ( 1/4)

Simplify the expression inside the parentheses

Rewriting the constant

16/81 = 2^4 / 3^4 = (2/3) ^4

Next the x terms

x^11 / x^7

We know that a^b / a^x = a^ ( b-c)

x^ (11-7) = x^4

And finally the y term

y^8/ y^6 = y^( 8-6) = y^2

(  (2/3) ^4 x^4 y^2) ^ ( 1/4)

We know that (ab) ^ c = a^ c * b^c

 (2/3) ^4 ^ 1/4   ( x^4 ^ 1/4   ( y^2) ^ ( 1/4)

We know that a^ b^ c = a^ ( b*c)

(2/3) ^4 ^ 1/4   ( x^4 ^ 1/4   ( y^2) ^ ( 1/4)

( 2/3) ^ ( 4*1/4)  * x^ ( 4*1/4)   * y ^ ( 2 ^ 1/4)

2/3 * x *  y ^ 2/4

2/3x  y ^ 2/4

2/3 x $\sqrt[4]{y^2}$

Answer 2

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▹ Answer

See below for attached work.

▹ Step-by-Step Explanation

Hope this helps!

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