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blondinia [14]
3 years ago
12

2. What is the exact area of a circle having radius 7 in.?

Mathematics
1 answer:
Viefleur [7K]3 years ago
7 0

Answer: 54 in^{2}

Step-by-step explanation:

Area of a circle = πr^{2}

Area = \frac{22}{7} x 7 x 7   ( π = \frac{22}{7} )

Area = 22 x7

Area = 154 in^{2}

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You roll two fair dice, a green one and a red one. (a) What is the probability of getting a sum of 7? (Enter your answer as a fr
Lera25 [3.4K]

Answer:

a) 0.167  b)0.056  c)0.023

Step-by-step explanation:

We are given the following information:

Sample space = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

                            (2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

                            (3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

                            (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

                            (5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

                            (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Total number of outcomes = 36

Formula:

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

a) P(sum is 7)

Sum 7 possible outcomes = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

= P = \displaystyle\frac{6}{36} = \displaystyle\frac{1}{6} = 0.167

b) P(sum is 11)

Sum 11 possible outcomes = {(5,6), (6,5)}

= P = \displaystyle\frac{2}{36} = \displaystyle\frac{1}{18} = 0.056

c) P( sum is 7 or sum is 11)

= P(\text{sum is 7}) + P(\text{sum is 11}) - (P(\text{sum is 7}\cap \text{sum is 11})) \\= \displaystyle\frac{6}{36} + \displaystyle\frac{2}{36} + 0\\\\= \displaystyle\frac{8}{36} = \displaystyle\frac{2}{9} = 0.223

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The profit would be B. 58.02. (240-210.99 = 29.01, then 29.01 x 2 = 58.02) Hope this helps :)
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