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3 years ago

Anwser themm!!!!!! HELP ASAP MATH

Mathematics

1 answer:

tigry1 [53]3 years ago

8 0

Answer:

Please see the detailed answers below:

Step-by-step explanation:

Solution 1:

Sandwich = $9.25

Salad = $4.35

Tax = 7.5%

=> ($9.25 + $4.35) x 7.5 / 100 = 13.6 x 0.075 = $1.02

The amount of Tax on Veena's meal is $1.02

Solution 2:

Book read by Christian = (1/4) / (2/3) = (1/4) x (3/2) = 3/8

Christian will read 3/8 books per week.

Solution 3:

Sale Price = (100 - Discount Rate) x Cost Price

Let Y = Sale Price

By Putting the values in above equation:

Y = (100 - 45) x $650

Y = 0.55 x $650

Y = $357.5

Hence the Sale Price of the bicycle will be $357.5

Solution 4:

Percent error = [(Experimental Value - Accepted Value) / Accepted Value] x 100

Percent error = [(15.5 - 14.5) / 14.5] x 100

Percent error = [1 / 14.5] x 100

Percent error = 2.2%

Hence the percent error in Mark's estimate is 2.2%

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6.9ft
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3 years ago

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(6x10^2)/(3x10-5) help what is this in standard form?

Tasya [4]

<u>Answer: </u>

The standard form of $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ is 20,00,0000

<u>Solution: </u>

Given that $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ ---- eqn 1

To write $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ in standard form,

We know that $\bold{\frac{1}{a^{-m}} = a^{m}}$ .So $\frac{1}{10^{-5}}$ becomes $10^{5}$ .

Now eqn 1 becomes,

$= \frac{6 \times 10^{2}}{3} \times 10^{5}$ ----- eqn 2

We know that $\bold{a^{m} \times a^{n}=a^{m+n}}$ , so $10^{2} \times 10^{5} = 10^{7}$

Now eqn 2 becomes,

$= \frac{6}{3} \times 10^{7}$

$= 2 \times 10^{7}$ ---- eqn 3

Expanding $10^{7}$ :

Here 10 is the base term and 7 is the exponent value. So base term 10 is multiplied by itself 7 times.

$10^{7} = 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10$

Now eqn 3 becomes,

$= 2 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10$

= 20,00,0000

Hence the standard form of $\frac{6 \times 10^{2}}{3 \times 10^{-5}}$ is 20,00,0000

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3 years ago

Madison claims that two data sets with the same median will have the same variability. Which data set would provide good support

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Answer:

Step-by-step explanation:

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An opaque bag contains 5 blu marbles, 4 green marbles, and 3 red marbles. If two consecutive marbles are drawn without replaceme

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Answer:

Probability[Choosing red and blue consecutive] = 5/44

Step-by-step explanation:

Given:

Number of blue marble = 5

Number of green marble = 4

Number of red marble = 3

Find:

Probability[Choosing red and blue consecutive]

Computation:

Probability of red marble = Number of red marble / Total marble

Probability of red marble = 3 / [5 + 4 + 3]

Probability of red marble = 3 / 12

Probability of red marble = 1/4

Probability of next blue marble = Number of blue marble / [Total marble - 1]

Probability of next blue marble = 5 / [Total marble - 1]

Probability of next blue marble = 5 / [12 - 1]

Probability of next blue marble = 5 / 11

Probability[Choosing red and blue consecutive] = Probability of red marble x Probability of next blue marble

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3 years ago