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marusya05 [52]
3 years ago
9

Use elimination to solve this system of equations. 2r + 3s= 9 and 3r + 2s= 12

Mathematics
2 answers:
timama [110]3 years ago
7 0
<span>2r + 3s= 9 <=> -6r -9s = -27;</span>
<span>3r + 2s= 12 <=> 6r + 4s = 24;
                    => 0*r -5*s = -3 => s = 3/5;

2*r + 3*(3/5) = 9<=> 10*r + 9 = 45 <=> 10*r = 36 => r = 18/5;
</span>
Rzqust [24]3 years ago
6 0

Answer:

(18/5,3/5)

Step-by-step explanation:

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A board that measures 34 3 4 feet long is cut into 6 equal pieces. What is the length of each piece?
kifflom [539]

Answer 1.5

Divide 9/6= "Answer"

Where did the 9 come from?

There are 12in in a foot so 3/4 = 9in

8 0
3 years ago
Read 3 more answers
BRAINLIEST if correct
Mila [183]

Answer:

A=38.88 or 38.9

Step-by-step explanation:

If both are similar then the 9 and the 7.2 are the same

9-7.2= 1.8

9x6=54

7.2-1.8=5.4

7.2x5.4=38.88 or 38.9

4 0
2 years ago
Word problem that represents 8 times -0.25
lubasha [3.4K]

Answer:

If bob buys 8 choclates, which each of them are 0.25 dollars each, how much money does he have if he has 0 dollars?

Step-by-step explanation:

8 0
2 years ago
If f(x) = 2x^4, then f'(3) =
valkas [14]

To find f'(3) (f prime of 3), you must find f' first.  f' is the derivative of the function f(x).

Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.

The power rule for derivatives is \frac{d}{dx} [x^{n} ] =nx^{n-1}.  In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.

f'(x) = \frac{d}{dx}(2x⁴)

f'(x) = 2(4)x³

f'(x) = 8x³

Now, to find f'(3), plug 3 into your derivative.

f'(3) = 8(3)³

f'(3) = 216

<h3>Answer:</h3>

f'(3) = 216

6 0
2 years ago
Add 0.0025 kg, 1750 mg, 2.25 g, and 825,000 μg, and express the answer in grams.
kozerog [31]

Answer:

6.75g

Step-by-step explanation:

The first step is converting everything to grams, by rules of three. Then we add.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.

Unit conversion problems, like this one, is an example of a direct relationship between measures.

First step: 0.0025kg to g

Each kg has 1000g, so:

1kg - 1000g

0.0025kg - xg

x = 1000*0.0025 = 2.5g

0.0025kg = 2.5g

Second step:  1750 mg

Each g has 1000mg, so:

1g - 1000mg

xg - 1750mg

1000x = 1750

x = \frac{1750}{1000}

x = 1.75g

1750 mg = 1.75g

2.25g - OK

Third step: 825,000 μg to g

Each g has 1,000,000 ug, so:

1g - 1,000,000 ug

xg - 825,000 ug

1,000,000x = 825,000

x = \frac{825,000}{1,000,000}

x = 0.25g

825,000 μg = 0.25g

Final step: adding everyting

0.25g + 2.25g + 1.75g + 2.50g = 6.75g

5 0
3 years ago
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