<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
C. 16 cm
Step-by-step explanation:
Top side: 2 + 4 = 6
Right side: 1 + 1 = 2
Bottom: 2 + 4 = 6
Left side: 1 + 1 = 2
6+6+2+2 = 16 cm.
P = $70, p = 2.5% = 0.025
q = 1 + 0.025 / 12 = 1.002
Future value of a periodic deposit:
A = P · q · ( q^30 - 1 ) / ( q - 1 )
A = 70 · 1.002 · ( 1.002^30 - 1 ) / ( 1.002 - 1 )
A = $2,166
Answer:
He will have $2.166 in 30 months.
The angle does not matter. Think of it as finding the other side to a triangle. Use
a=39 (line AB)
b=b (the leg we need to find)
c=89 (line BD)
(subtract the 1521 from both sides)
(square root both sides)
b = 80
AD=80
