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3 years ago

What is the addititve inverse of 63

Mathematics

2 answers:

dybincka [34]3 years ago

8 0

Answer:

It is -63

Step-by-step explanation:

What you add to a number to get zero. The negative of a number.

denis23 [38]3 years ago

3 0

Additive Inverse of 63 = -63
Since the additive inverse of 63 is -63, additive inverse is also known as the opposite number.

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san4es73 [151]

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It will have the equation y=x/2+a where a is found by plugging in the given point: 4=-1+a, so a=5.
Therefore y=x/2+5. (This can also be written 2y=x+10 or x-2y+10=0)

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3 years ago

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Michael pays his cell phone service provider $49.95 per month for 500 minutes. Any additional minutes used cost $0.15 each. In J

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y = total cost used.

x = additional minutes

y = $49.95 + $0.15x

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3 years ago

Suppose you received a score of 95 out of 100 on exam 1 . The mean was 79 and the standard deviation was 8 . If your score on ex

Schach [20]

Answer:

You did the same on both exams.

Step-by-step explanation:

To compare both the scores, we need to compute the z scores of both the exams and then compare the values. The formula for z-score is:

Z = (X - μ)/σ

Where X = score obtained

μ = mean score

σ = standard deviation

For Exam 1:

Z = (95 - 79)/8

= 16/8

Z = 2

For Exam 2:

Z = (90 - 60)/15

= 30/15

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3 years ago

25(M-2)=650 what is M ?

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Step-by-step explanation:

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A bacteria culture starts with 12,000 bacteria and the number doubles every 50 minutes.

Vlada [557]

Answer:

a) $y=12000(2)^{\frac{t}{50}}$

b) Approx. 27,569 bacteria

c) About 103 minutes

Step-by-step explanation:

This will follow exponential modelling with form of equation shown below:

$y=Ab^{\frac{t}{n}}$

Where

A is the initial amount (here, 12000)

b is the growth factor (double, so growth factor is "2")

n is the number of minutes in which it doubles, so n = 50

Substituting, we get our formula:

$y=Ab^{\frac{t}{n}}\\y=12000(2)^{\frac{t}{50}}$

To get number of bacteria after 1 hour, we have to plug in the time into "t" of the formula we wrote earlier.

Remember, t is in minutes, so

1 hour = 60 minutes

t = 60

Substituting, we get:

$y=12000(2)^{\frac{t}{50}}\\y=12000(2)^{\frac{60}{50}}\\y=12000(2)^{\frac{6}{5}}\\y=27,568.76$

The number of bacteria after 1 hour would approximate be 27,569 bacteria

To get TIME to go to 50,000 bacteria, we will substitute 50,000 into "y" of the equation and solve the equation using natural logarithms to get t. Shown below:

$y=12000(2)^{\frac{t}{50}}\\50,000=12,000(2)^{\frac{t}{50}}\\4.17=2^{\frac{t}{50}}\\Ln(4.17)=Ln(2^{\frac{t}{50}})\\Ln(4.17)=\frac{t}{50}*Ln(2)\\\frac{t}{50}=\frac{Ln(4.17)}{Ln(2)}\\\frac{t}{50}=2.06\\t=103$

After about 103 minutes, there will be 50,000 bacteria

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3 years ago