<span>There are several possible events that lead to the eighth mouse tested being the second mouse poisoned. There must be only a single mouse poisoned before the eighth is tested, but this first poisoning could occur with the first, second, third, fourth, fifth, sixth, or seventh mouse. Thus there are seven events that describe the scenario we are concerned with. With each event, we want two particular mice to become diseased (1/6 chance) and the remaining six mice to remain undiseased (5/6 chance). Thus, for each of the seven events, the probability of this event occurring among all events is (1/6)^2(5/6)^6. Since there are seven of these events which are mutually exclusive, we sum the probabilities: our desired probability is 7(1/6)^2(5/6)^6 = (7*5^6)/(6^8).</span>
I guess complement should be 1- 0.35 = 0.65 !!
Answer:
D. Yes,because every x-value corresponds to exactly one y-value.
Step-by-step explanation:
The given ordered pairs are;
{
}
We do not have the same x-value corresponding to more than one y-value.
We can see from the ordered pairs that every x-value corresponds to exactly one y-value.
Therefore the graph of this relation will pass the vertical line test.
Answer:
6x
Step-by-step explanation:
because in front of x^3 there is 6x and also the qn has asked to find the coefficient of x^3
Answer:
44000(1+.0825)^10=$97214.65≈$97215 to the nearest dollar
