All sides are equal in an equilateral triangle and the perpendicular bisects the side too.
so BC will be bisected and the segments be 5 each.
you can use Pythagoras theorem to find the altitude length, hypotenuse will be one side of the triangle.
$h^2=100-25=75$
$h=\sqrt{75}=5\sqrt3$
B, make a table of possible values
the best way to do it is actually not listed
to have max area with minimu perimiter, try to get the sides as close measure to each other as possible
I would pick B though
I'm pretty sure they all have the same number. You see, there are no numbers, so the equations are all y= so they are all the same line. The answer is D!
hope this helped :)
This is a quadratic equation:
y = a x² + b x + c, a > 0 ( opening upward )
The zeroes are: ( - 1 , 0 ) and ( 4, 0 ).
y = a ( x - x 1 ) ( x - x 2 )
y = a ( x + 1 ) ( x - 4 )
y = a ( x² - 4 x + x - 4 )
y = a ( x² - 3 x - 4 )
Answer:
h = (24 - 3x - x²)/(2x + 3)
Step-by-step explanation:
Surface area:
2(x × (x + 3)) + 2(x)h + 2(x + 3)h
2(x² + 3x) + 2xh + 2(x + 3)h = 48
x² + 3x + xh + xh + 3h = 24
h(2x + 3) = 24 - x² - 3x
h = (24 - 3x - x²)/(2x + 3)
