The area of the shaded region is going to be the area of the rectangle minus the area of the square.
Area of a rectangle is L * W.
A = L * W
A = (x + 10)(2x + 5)
A = x(2x + 5) + 10(2x + 5)
A = 2x^2 + 5x + 20x + 50
A = 2x^2 + 25x + 50 .....this is the area of the rectangle
area of a square is : A = a^2...where a is one side
A = (x + 1)^2
A = (x + 1)(x + 1)
A = x(x + 1) + 1(x + 1)
A = x^2 + x + x + 1
A = x^2 + 2x + 1
now we subtract the area of the square from the area of the rectangle to get the area of the shaded region.
2x^2 + 25x + 50 - (x^2 + 2x + 1) =
2x^2 + 25x + 50 - x^2 - 2x - 1 =
x^2 + 23x + 49 <== the area of the shaded region
The first step is to combine like terms. So u would do 2-6. You then get -4 then u just bring everything else down. So now u should have this :
8x -4 = 4x + 8 + 3x
Now you do the same thing to the other side. U combine like terms which in this case are 4x and 3x. So u just do 4+3 which is 7 so now u have 7x. So now ur equation would be:
8x -4 = 7x +8
Now u do the inverse of 7 which would be -7 and u do that on both sides. So it would look like this :
8x -4 = 7x + 8
-7x. -7x
So now 7 and -7 cancel each other other and 8 -7 is 1 so now u have one x. So ur equation would now look like this:
1x -4 = 8
Now u do the inverse of negative 4 which is +4. So you would add 4 on both sides on both sides. Like shown:
1x -4 = 8
+4 +4
So u just add 8 + 4 which is 12. Now since anything times 1 is itself ur answer will be X=12
Hope this helped
Answer:
D. dA/dt = 4h dh/dt in²/sec
Step-by-step explanation:
Given:
A = wh
w = 2h
Substitute:
A = 2h²
Take derivative with respect to time:
dA/dt = 4h dh/dt
dA/dt has units of in²/sec.
Answer:
6
Step-by-step explanation:
3/4 ÷ 1/8
Copy dot flip
3/4 * 8/1
Rewriting
3/1 * 8/4
3/1 * 2/1
6
