F(x)=5x^2 Has minimum (0,0)
g(x) = f(x) + 2 Shifts the graph two units up, then the minimum is 2+0=2.
h(x) = g(x+4) Shifts the graph four units left, then the minimum is at 0-4 = -4.
Then h(x) = 5(x+4)^2 + 2 has the minimum (-4,2)
And p(x) = -5(x+4)^2 + 2 has the maximum (-4,2)
27-5 = 22
22/11 = 11
there are 11 boys at the party
expression = b+5
<span> r+5 </span><span>r^2+4r-21
</span><span>-------------- / --------------------
r^2+5r-14 </span><span>r-2
</span> r+5 r-2
= -------------- x --------------------
r^2+5r-14 r^2+4r-21
r+5 r-2
= -------------- x --------------------
(r+7)(r-2) (r+7)(r-3)
r+5
= -----------------
(r+7)^2 (r-3)
The value of the number can be equal to or less than -3
