To solve this problem, we make use of the z statistic. The formula for the z score is:z score = (x – u) / swhere x is the sample value = 0.90, u is the sample mean = 0.917, and s is the standard deviation = 0.005
Therefore:z score = (0.90 – 0.917) / 0.005z score = -3.4
From the standard probability tables, the p-value for a right tailed test of z = -3.4 is:P = 0.9997
Therefore there is a 99.97% chance that it will be above 0.90 mm
Answer:
√20 or 4.47 ish
Step-by-step explanation:
√(1--3)²+(-2--4)²
√(1+3)²+(-2+4)²
√(4)²+(2)²
√16+4
√20
4.47 ish
(Hopefully this is correct, have a nice day!)
