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mart [117]
3 years ago
15

Match the words (1-10) with the definitions (A-J)

Computers and Technology
2 answers:
BARSIC [14]3 years ago
6 0

Answer:

10. A

9. E

8. B

7. H

6. C

5.G

4. I

3. F

2.D

1. J

sergij07 [2.7K]3 years ago
3 0

Answer:

1 - I

2 - A

3 - B

4 - E

5 - J

6 - C

7 - H

8 - D

9 - F

10 - G

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Who are griefers?
S_A_V [24]

D) People who try to irritate you and harass you in online games

7 0
3 years ago
Create a new Java project/class called Examine1. Prompt user as to how many numbers they would like to enter. Use a cumulative s
Zinaida [17]

Answer:

Explanation:

The following code is written in Java and like requested prompts the user for a number to continue or a letter to exit. Then loops and keeps adding all of the numbers to the sum variable and adding 1 to the count for each number entered. Finally, it prints the sum and the average using printf and the variables.

import java.util.Scanner;

class Examine1 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int sum = 0;

       int count = 0;

       System.out.println("Enter a number to continue or a letter to exit.");

       while(in.hasNextInt()) {

           System.out.println("Enter a number:");

           sum += in.nextInt();

           count += 1;

       }

       System.out.printf("The sum is %s.%n", sum);

       System.out.printf("The average is %s.", (sum / count));

   }

}

8 0
3 years ago
Implement a sorting algorithm and sort the vocab array (found below) alphabetically. For this question, do not define or use an
Stolb23 [73]

Answer:

vocab = [ "Libraries", "Bandwidth", "Hierarchy", "Software", "Firewall", "Cybersecurity","Phishing", "Logic", "Productivity"]

print(vocab)

needNextPass = True

k = 1

#list = [x.lower() for x in list]

while k < len(vocab)-1 and needNextPass:

   # List may be sorted and next pass not needed

   needNextPass = False

   for i in range(len(vocab) - k):

       if vocab[i] > vocab[i + 1]:

           # swap list[i] with list[i + 1]

           temp = vocab[i]

           vocab[i] = vocab[i + 1]

           vocab[i + 1] = temp

           needNextPass = True  # Next pass still needed

print(vocab)

Explanation:

I hope this helps you!

3 0
4 years ago
Could you describe in 3 lines what an API is?
Brilliant_brown [7]

An API is in computer programming. So it is an application programming interface is a set of several subroutine definitions. Also consists of Communication protocols and tools for you to build software.

Also known by its full names, Application Programming Interface. I was just going to ask it myself actually.

I hope this helps and good question?

8 0
4 years ago
1- Design a brute-force algorithm for solving the problem below (provide pseudocode): You have a large container with storage si
sladkih [1.3K]

Answer:

Pseudocode is as follows:

// below is a function that takes two parameters:1. An array of items 2. An integer for weight W

// it returns an array of selected items which satisfy the given condition of sum <= max sum.

function findSubset( array items[], integer W)

{

initialize:

maxSum = 0;

ansArray = [];

// take each "item" from array to create all possible combinations of arrays by comparing with "W" and // "maxSum"

start the loop:

// include item in the ansArray[]

ansArray.push(item);

// remove the item from the items[]

items.pop(item);

ansArray.push(item1);

start the while loop(sum(ansArray[]) <= W):

// exclude the element already included and start including till

if (sum(ansArray[]) > maxSum)

// if true then include item in ansArray[]

ansArray.push(item);

// update the maxSum

maxSum = sum(ansArray[items]);

else

// move to next element

continue;

end the loop;

// again make the item[] same by pushing the popped element

items.push(item);

end the loop;

return the ansArray[]

}

Explanation:

You can find example to implement the algorithm.

3 0
3 years ago
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