3 years ago

Line a pass through (1,-1),and (1,3)

1 answer:

6 0

These two points have the same x coordinate, 1, so it is a vertical line that passes 1 on the x axis,
the equation of the line is x=1

You might be interested in

{x | x I, x ≤ 3} {..., 0, 1, 2, 3} {4, 5, 6, 7, ...} {3, 4, 5, 6, ...}

Oksanka [162]

Answer:

I'm pretty sure its...

{-1, 0, 1, 2, 3}

{4, 5, 6, 7, 8}

{3, 4, 5, 6,7 }

7 0

3 years ago

Sally goes out to lunch and has the option

castortr0y [4]

Hello,

well, that depend on what your asking. comment the answer choices so I can answer this question for you!

-bell

3 0

3 years ago

Please answer correctly !!!!!!!!!!!!! Will mark Brianliest pleaseeeee !!!!!!

Dimas [21]

Answer:

2sqrt(10)

Step-by-step explanation:

Use the Pythagorean theorem.

x^2 + 3^2 = 7^2

x^2 + 9 = 49

x^2 = 40

x = sqrt(40)

x = 2sqrt(10)

7 0

3 years ago

12 out of 30 tickets sold were early admission what percentage of tickets were early admission tickets

bezimeni [28]

Answer:

40%

Step-by-step explanation:

12 divided by 30 will give you 0.4

7 0

3 years ago

How to factor z²-4z+4

allochka39001 [22]

$\implies {\blue {\boxed {\boxed {\purple {\sf { \: ({ \: z - 2 \: })^{2} \: }}}}}}$

$\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}$

${z}^{2} - 4z + 4$

$= {z}^{2} - 2z - 2z + 4$

Taking " $z$ " as common from first two terms and " $2$ " from last two terms, we have

$= z \: ( \: z - 2 \: ) - 2 \: ( \: z - 2 \: )$

Taking the factor $(z-2)$ as common,

$= ( \: z - 2 \: )( \: z - 2 \: )$

$= {( \: z - 2 \: )}^{1 + 1}$

$= ({ \: z - 2 \: })^{2}$

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35❦}}}}}$

8 0

3 years ago