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3 years ago

Solve. 6x – 25 = 3(4x + 9) + 14 How do I do this or like just do the steps for me?

Mathematics

2 answers:

Mashcka [7]3 years ago

5 0

Answer:

x=-11

Step-by-step explanation:

6x – 25 = 3(4x + 9) + 14

Distribute

6x – 25 = 12x +27 + 14

Combine like terms

6x – 25 = 12x +41

Subtract 6x from each side

6x -6x-25 = 12x-6x+41

-25 = 6x+41

Subtract 41 from each side

-25-41 = 6x+41-41

-66 = 6x

Divide each side by 6

-66/6= 6x/6

-11=x

rodikova [14]3 years ago

4 0

Answer:

I think it is - 11.

Step-by-step explanation:

6x - 25 = 12x + 27 + 14

6x - 12x = 25 + 27 + 14

- 6x = 52 + 14

- 6x = 66

x = - 11

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Luden [163]

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3 years ago

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We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.

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3 years ago