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frutty [35]
3 years ago
6

Solve. 6x – 25 = 3(4x + 9) + 14 How do I do this or like just do the steps for me?

Mathematics
2 answers:
Mashcka [7]3 years ago
5 0

Answer:

x=-11

Step-by-step explanation:

6x – 25 = 3(4x + 9) + 14

Distribute

6x – 25 = 12x +27 + 14

Combine like terms

6x – 25 = 12x +41

Subtract 6x from each side

6x -6x-25 = 12x-6x+41

-25 = 6x+41

Subtract 41 from each side

-25-41 = 6x+41-41

-66 = 6x

Divide each side by 6

-66/6= 6x/6

-11=x

rodikova [14]3 years ago
4 0

Answer:

I think it is - 11.

Step-by-step explanation:

6x - 25 = 12x + 27 + 14

6x - 12x = 25 + 27 + 14

- 6x = 52 + 14

- 6x = 66

x = - 11

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sergiy2304 [10]

We have been given a graph of function g(x) which is a transformation of the function f(x)=3^x

Now we have to find the equation of g(x)

Usually transformation involves shifting or stretching so we can use the graph to identify the transformation.


First you should check the graph of f(x)=3^x

You will notice that it is always above x-axis (equation is x=0). Because x-axis acts as horizontal asymptote.

Now the given graph has asymptote at x=-2

which is just 2 unit down from the original asymptote x=0

so that means we need shift f(x), 2 unit down hence we get:

y=3^x


but that will disturb the y-intercept (0,1)

if we multiply 3^x by 3 again then the y-intercept will remain (0,1)

Hence final equation for g(x) will be:

g(x)=3(3^x)-2


5 0
3 years ago
Mr. Lance keeps a jar of candy on his desk for students to pick from when they do well on a test. The jar contains 5 Snickers, 2
Oxana [17]
3/14 for the first kid and 2/13 for the 2nd kid
6 0
3 years ago
Read 2 more answers
Find the x - and y-intercepts of the graph of the linear equation –6x + 9y = -18
natulia [17]

Answer:

x-intercept = -6      y-intercept = 9

Step-by-step explanation:

4 0
3 years ago
#1: Solve the inequality below.<br> -3x + 5 &lt; -19
frosja888 [35]

Explanation: Just like any of your two-step equations,

in this inequality,  start by isolating the x term which in this

case is -3x by subtracting 5 from both sides.

That leaves you with -3x < -24.

To get x by itself, divide both sides by -3 but watch out.

When you multiply or divide both sides of an inequality by a

negative number, you must switch the direction of the inequality sign.

So we have x < 8 and put your final answer in

set notation and it look like this → {x: x < 8}.

4 0
3 years ago
The box plot shows the undergraduate in-state tuition per credit hour at four-year public colleges. 0 300 600 900 1,200 $1,500 a
kkurt [141]

Answer:

(a) The median estimate is 450.

(b) The first and third quartiles are 300 and 750 respectively.

(c) The interquartile range is 450.

(d) The particular value which is less than 150 or it is more than 1200, is considered as an outlier.

(e) Yes, there is one outlier in our data which is the value of 1,500.

(f) The distribution is positively skewed.

Step-by-step explanation:

We are given that the box plot shows the undergraduate in-state tuition per credit hour at four-year public colleges. 0, 300, 600, 900, 1,200, 1,500.

(a) As we can see in the box plot that the middlemost data lies between 300 and 600, that means;

Median is given by the average of the two numbers, i.e;

             Median =  \frac{300+600}{2}

                           =  \frac{900}{2}  = 450

So, the median estimate is 450.

(b) As we know that the first quartile represents 25% of the data values and the third quartile represents 75% of the data values.

So, from the box plot given; we can observe that the first quartile, Q_1 = 300 and the third quartile lies between the values of 600 and 900, i.e;

Third quartile, Q_3 = \frac{600+900}{2}

                             =  \frac{1500}{2}  = 750

So, the first and third quartiles are 300 and 750 respectively.

(c) The interquartile range is given by the following formula;

          Interquartile range = Third quartile - First quartile

                                          =  Q_3-Q_1

                                          =  750 - 300 = 450

(d) From the box plot; it is clear that if the particular value is less than 150 or it is more than 1200, then it is considered as an outlier.

(e) Yes, there is one outlier in our data which is the value of 1,500.

(f) The distribution is positively skewed because the more values are on the right side of the curve and it skewed towards the right.

4 0
4 years ago
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