The minimum number of comparisons to find the smallest number from 5 integers is 4.
<h3>How to find the Smallest Integer?</h3>
Let the five numbers be a,b,c,d and e.
Let s be an integer
Comparison 1:
a and b will be compared first and the smaller number of them will be equal to s
Comparison 2:
Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.
Comparison 3:
Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison
Comparison 4:
Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.
After 4th comparison, s will be equal to smallest number of 5 integers.
Thus;
Total comparisons = 4
Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.
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Inequalities are used to represent unequal expressions.
The solution set to 
is: 
The inequality is given as:
From the inequality above, we have the following observation.
- The value of variable x starts from 7/16 (inclusive)
- The value of variable x has no end (i.e. infinity)
Because, 7/16 is inclusive of the values of x, we make use of the open square bracket i.e. [
We treat 
, as an exclusive value. So, we make use of the close parenthesis i.e. )
Hence, the solution set is:
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Answer:
and u will find it
Explanation:
all u have to do is sumtaxk all of it
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