Answer:
The proof is explained step-wise below :
Step-by-step explanation :
For better understanding of the solution see the attached figure :
Given : ABCD is a Parallelogram ⇒ AB ║ DC and AD ║ BC
Now, F lies on the extension of DC. So, AB ║ DF
To Prove : ΔABE is similar to ΔFCE
Proof :
Now, in ΔABE and ΔFCE
∠ABE = ∠FCE ( alternate angles are equal )
∠AEB = ∠FEC ( Vertically opposite angles )
So, by using AA postulate of similarity of triangles
ΔABE is similar to ΔFCE
Hence Proved.
Answer:
B.
Step-by-step explanation:
because they have the same base and it's a multiplication so you have to add the exponents
Multiply 14 to each term: 14a+70+84b
Answer:
see explanation
Step-by-step explanation:
The 2 angles form a right angle, thus their sum is 90°, hence
4x + 7 + 35 = 90
4x + 42 = 90 ( subtract 42 from both sides )
4x = 48 ( divide both sides by 4 )
x = 12
-----------------------------------------------------
To calculate the slope m use the slope formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (1, 4) ← 2 points on the line
m = 
= 
= 4
