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Alenkinab [10]
4 years ago
12

Which expression is equivalent to (7x-5) - (3x - 2)

Mathematics
2 answers:
LuckyWell [14K]4 years ago
6 0

Answer:

(c) 4x - 7

Step-by-step explanation:

7x - 3x

= -4x

-5 -2

= -7

4x - 7

zalisa [80]4 years ago
6 0
The answer to the problem is c) 4x-7
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A. y = 3x + 1 and x + y = 5<br> How do you solve this?
KonstantinChe [14]
The first on is X= -1/3 and the second on is might be 5 but I am not sure also I may not be 100% but I think iits right hope it helped
3 0
3 years ago
Read 2 more answers
Which of the following equations is graphed below? 3 x - 5 y = 2 3 x + 2 y = 4
34kurt

Answer:

I am pretty sure it is 3x-5y=4

Step-by-step explanation:

You have to put the equation in point slope form and 3x-5y=4 in point slope form is y=3/5x-4/5

3 0
3 years ago
What is the volume of a rectangular prism with a length of 7 centimeters, a width of 3 centimeters, and a height of 2 centimeter
fiasKO [112]

Answer:

42cm³

Step-by-step explanation:

7*2*3=42

7*2=14

14*3=42

42

5 0
3 years ago
What is the measure of ∠w, rounded to the nearest degree? 19° 19° 32° 32° 56° 56° 71° 71° a horizontally-aligned scalene triangl
ella [17]

Answer:

  (d)  71°

Step-by-step explanation:

The desired angle in the given isosceles triangle can be found a couple of ways. The Law of Cosines can be used, or the definition of the sine of an angle can be used.

<h3>Sine</h3>

Since the triangle is isosceles, the bisector of angle W is an altitude of the triangle. The hypotenuse and opposite side with respect to the divided angle are given, so we can use the sine relation.

  sin(W/2) = Opposite/Hypotenuse

  sin(W/2) = (35/2)/(30) = 7/12

Using the inverse sine function, we find ...

  W/2 = arcsin(7/12) ≈ 35.685°

  W = 2×36.684° = 71.37°

  W ≈ 71°

<h3>Law of cosines</h3>

The law of cosines tells you ...

  w² = u² +v² -2uv·cos(W)

Solving for W gives ...

  W = arccos((u² +v² -w²)/(2uv))

  W = arccos((30² +30² -35²)/(2·30·30)) = arccos(575/1800) ≈ 71.37°

  W ≈ 71°

7 0
2 years ago
The coordinates of the vertices of △PQR are P(1, 4) , Q(2, 2) , and R(−2, 1) . The coordinates of the vertices of △P′Q′R′ are P′
sveticcg [70]

ANSWER


The correct  answer is B


<u>EXPLANATION</u>

If we analyse the coordinates carefully, you realize there is a mapping of

(x,y)\rightarrow(-x,y)

This is a reflection in the y-axis.


Since the transformation is a reflection, the shape is preserved. Therefore, the image triangle P'Q'R' of triangle

PQR are congruent.



5 0
3 years ago
Read 2 more answers
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