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Alenkinab [10]
3 years ago
12

Which expression is equivalent to (7x-5) - (3x - 2)

Mathematics
2 answers:
LuckyWell [14K]3 years ago
6 0

Answer:

(c) 4x - 7

Step-by-step explanation:

7x - 3x

= -4x

-5 -2

= -7

4x - 7

zalisa [80]3 years ago
6 0
The answer to the problem is c) 4x-7
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9/4 divided by 3/8= 9/4 x 8/3
erma4kov [3.2K]

Answer:

9/4:3/8=9/4×8/3=72/12=24/4=6/1=6

7 0
3 years ago
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i know this is probably simple but ive forgotten how to do it and i cant find it in my notes help appreciated!
Soloha48 [4]

Answer:

? = 13.6

Step-by-step explanation:

the angle between a tangent and the diameter = 90°

Then the triangle is right with legs 2 × 6 = 12 and 6.4

using Pythagoras' identity in the right triangle.

the square on the hypotenuse is equal to the sum of the squares on the legs , that is

? ² = 12² + 6.4² = 144 + 40.96 = 184.96 ( take square root of both sides )

? = \sqrt{184.96} = 13.6

6 0
2 years ago
7th grade math help me plzzz
murzikaleks [220]

Answer:

a. -7 + 3

b. draw 7 negatives + 7 positives

Step-by-step explanation:

5 0
3 years ago
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Solve for
faust18 [17]

Given equation : n(17+x)=34x−r.

We need to solve it for x.

Distributing n over (17+x) on left side, we get

17n + nx  = 34x - r.

Adding r on both sides, we get

17n+r + nx  = 34x - r+r.

17n + r + nx = 34x.

Subtracting nx from both sides, we get

17n + r + nx-nx = 34x-nx

17n + r = 34x -nx.

Factoring out gcf x on right side, we get

17x + r = x(34-n).

Dividing both sides by (34-n), we get

\frac{(17x + r)}{(34-n)} = \frac{x(34-n)}{(34-n)}

\frac{(17x + r)}{(34-n)} = x

<h3>Therefore, final answer is x=\frac{(17x + r)}{(34-n)}.</h3>
7 0
3 years ago
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1) Two similar rectangles are shown. Which statement is true? A) The area of rectangle B is 1 3 the area of rectangle A. B) The
Arturiano [62]

Answer: C

Step-by-step explanation:

We know the scale factor is 6/2=3.

A) False. The ratio of the side lengths, not the areas, is 1 to 3.

B) False. Rectangle B is larger than Rectangle A.

C) The square of the ratio of the side lengths is the ratio of the areas.

D) False. The ratio of the side lengths, not the areas, is 1 to 3.

3 0
2 years ago
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