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VashaNatasha [74]
3 years ago
6

if there is 2 ducks ahead of a duck 2 ducks behind a duck & 1 duck in the middle. How many total ducks are there?

Mathematics
2 answers:
ki77a [65]3 years ago
6 0
There are 5 ducks
2 infront+2 behind+ 1 in the middle= 5
Serhud [2]3 years ago
5 0
There is 5 ducks in all


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Hi I also need help with this please and thank you
OverLord2011 [107]

Answer:

Step-by-step explanation:

y=mx+b where m=slope and b=y intercept

m=(y2-y1)/(x2-x1)

m=(-2-4)/(2+1)

m=-2 so far we have the slope

y=-2x+b, using point (2,-2) we can solve for b, the y intercept

-2=-2(2)+b

-2=-4+b

2=b so we have our line

y=-2x+2, slope is -2 and y intercept is 2

8 0
3 years ago
What is the graph of the equation? y=-2
Marrrta [24]
Your answer would look like this

8 0
3 years ago
Read 2 more answers
Estimate the quotient of 21.49 ÷ 3.76 using compatible numbers.
kvv77 [185]

The quotient of 21.49 ÷ 3.76 using compatible numbers is approximately 5.69

<h3>What are quotients?</h3>

Quotients are result derived from the ratio of two rational or integers. Given the expression

21.49 ÷ 3.76

Convert to fraction

21.49 ÷ 3.76 = 2140/100  ÷  376/100
21.49 ÷ 3.76 = 2140/376

21.49 ÷ 3.76 =  5.69

Hence the quotient of 21.49 ÷ 3.76 using compatible numbers is approximately 5.69

Learn more on quotient here: brainly.com/question/673545

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4 0
2 years ago
huong and kathyrn each day impeoved their yards by planting rose bushes and ornamental grass. they bought their supplies from th
marta [7]

Answer:

One rose bush = $3

One bunch of ornamental grass = $4

Step-by-step explanation:

We can set up a system of equations to solve for this. Let cost of 1 rose bush be r and cost of 1 ornamental grass be g. Thus we can form 2 equations:

14r+7g=70\\5r+14g=71

We can multiply the first equation by -2 so that we can eliminate g. Thus, we have:

(*-2)14r+7g=70\\5r+14g=71\\-------\\-28r-14g=-140\\5r+14g=71\\--------\\-23r=-69\\r=\frac{-69}{-23}=3

Thus, 1 rose bush is $3. Now plugging in r = 3 into the first original equation, we can solve for g:

14r+7g=70\\14(3)+7g=70\\42+7g=70\\7g=70-42\\7g=28\\g=\frac{28}{7}=4

Thus, 1 bunch of ornamental grass is $4.

5 0
3 years ago
6.6 as a mixed number
svet-max [94.6K]
It should be 6 3/5 If not I’m sorry
8 0
3 years ago
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