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3 years ago

A week has five school days in two weekends write a ratio in through where is comparing the first quantity to the second

Mathematics

1 answer:

yarga [219]3 years ago

8 0

Answer:

Step-by-step explanation:

You always take the number they give you first and use it as the first quantity.

So your answer is 5:2, five to two, or 5 to 2.

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Can you pls help me on this

Archy [21]

Hey there! :D

If m<A is the vertex, and it is isosceles, then the last two angles are equal.

All the angles in a triangle equal 180 degrees.

180-140= 40

40/2= 20

m<b= 20 degrees.

I hope this helps!
~kaikers

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4 years ago

Hello can you please help me posted picture of question

vichka [17]

Hello fellow user!

Here is something that may help you. ^.^

P(GG)=(8/12)(7/11)

P(GG)=56/132

P(GG)=14/33

The answer is .B! Please contact me for any further questions. Cheerio and have a lovely day.

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3 years ago

Read 2 more answers

Solve the proportion 16/50-x/156.25 x= ? explain

harkovskaia [24]

Is this your question?

4 0

4 years ago

Does anyone know how to do this? And can you also help me with this problem, thank you :)

GenaCL600 [577]

Multiply equation(2) with 4 so that coefficient of become same in both the equations(You can make coefficient of y same and can follow the following procedure.)
* Subtract (3) from (1)
* Divide both sides by -19
*Subtract 21 from both sides.
*Divide both sides by 4
so the solution is x= 3 and y= -7
Hope I helped you :)

6 0

3 years ago

Mr. Green teaches mathematics and his class recently finished a unit on statistics. The student scores on this unit are: 40 47 5

Harrizon [31]

Answer:

Mean = 64.46, Median = 62 and Mode = Bi-modal (50 and 62)

Range of the data is 55.

Step-by-step explanation:

We are given that Mr. Green teaches mathematics and his class recently finished a unit on statistics.

The student scores on this unit are: 40, 47, 50, 50, 50, 54, 56, 56, 60, 60, 62, 62, 62, 63, 65, 70, 70, 72, 76, 77, 80, 85, 85, 95.

We know that Measures of Central Tendency are: Mean, Median and Mode.

Mean is calculated as;

Mean = $\frac{\sum X}{n}$

where $\sum X$ = Sum of all values in the data

n = Number of observations = 24

So, Mean = $\frac{40+ 47+ 50+ 50+ 50+ 54+ 56+ 56+ 60 +60+ 62+ 62+ 62+ 63+ 65+ 70+ 70+ 72+ 76+ 77+ 80+ 85+ 85+ 95}{24}$

= $\frac{1547}{24}$ = 64.46

So, mean of data si 64.46.

For calculating Median, we have to observe that the number of observations (n) is even or odd, i.e.;

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2})^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}$

Now here in our data, the number of observations is even, i.e. n = 24.

So, Median = $\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}$

= $\frac{(\frac{24}{2})^{th}\text{ obs.} +(\frac{24}{2}+1)^{th}\text{ obs.} }{2}$

= $\frac{(12)^{th}\text{ obs.} +(13)^{th}\text{ obs.} }{2}$

= $\frac{62 + 62 }{2}$ = $\frac{124}{2}$ = 62

Hence, the median of the data is 62.

A Mode is a value that appears maximum number of times in our data.

In our data, there are two values which appear maximum number of times, i.e. 50 and 62 as these both appear maximum 3 times in the data.

This means our data is Bi-modal with 50 and 62.

The Range is calculated as the difference between the highest and lowest value in the data.

Range = Highest value - Lowest value

= 95 - 40 = 55

Hence, range of the data is 55.

5 0

4 years ago