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3 years ago

13

Express in the form 1 : n . Give n as a decimal. 10 : 4

1 answer:

Brut [27]3 years ago

5 0

Answer:

n=0.4

Step-by-step explanation:

10:4=5:2

to make 5 as 1, we will divide both 5 and 2 by 5

<h3> $\frac{5}{5}$ : $\frac{2}{5}$ =1:n</h3><h3>therefore, n= $\frac{2}{5}$ = 0.4</h3><h3 /><h3> </h3>

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How to write 25 percent of N

Eva8 [605]

25÷100=0.25 0.25×n=the percentage Or 0.25n Or 0.25•n

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4 years ago

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Help. Also, how do you give Brainliest?

lawyer [7]

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Edit: f(-1)= 1 then f(1)= -10.

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3 years ago

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Look at the attached file. <br><br> please show your work on how you got the answer

statuscvo [17]

Answer:

D

Step-by-step explanation:

$\frac{f(x)}{g(x)}$

= $\frac{2x+4}{2x^2+4x}$

Factor out 2 on the numerator and 2x on the denominator.

= $\frac{2(x+2)}{2x(x+2)}$

Cancel the factor (x + 2) on the numerator/ denominator

= $\frac{2}{2x}$ ← cancel the 2 on numerator/ denominator

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8 0

3 years ago

A right rectangular prism is packed with cubes of side length fraction 1 over 5 inch. If the prism is packed with 15 cubes along

Ann [662]

Given:

A right rectangular prism is packed with cubes of side length $\dfrac{1}{5}$ inch.

Prism is packed with 15 cubes along the length, 6 cubes along the width, and 5 cubes along the height.

To find:

The volume of the prism

Solution:

Side length of each cube $=\dfrac{1}{5}$ inch.

15 cubes along the length, so length of prism is

$l=15\times \dfrac{1}{5}=3\text{ inches}$

6 cubes along the width, so width of prism is

$b=6\times \dfrac{1}{5}=\dfrac{6}{5}\text{ inches}$

5 cubes along the height, so height of prism is

$h=5\times \dfrac{1}{5}=1\text{ inch}$

Now,

Volume of rectangular prism is

$V=l\times b\times h$

$V=3\times \dfrac{6}{5}\times 1$

$V=\dfrac{18}{5}$

$V=\dfrac{3\times 5+3}{5}$

$V=3\dfrac{3}{5}\text{ cubic inches}$

Therefore, the correct option is B.

7 0

3 years ago

20 pointss please help I appreciate it <333

ivanzaharov [21]

Answer:

DE = 7.07 RS = 11.04 not congruent

Step-by-step explanation:

Formula:

$d=\sqrt{(x2-x1)^2 + (y2-y1)^2}$

D (5,0) E (0,-5)

DE

$d=\sqrt{(0-5)^2 + ( -5 - 0)^2}$

$d=\sqrt{(-5)^2 + (-5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

d= 7.07

R (-5,-5) S (6,-6)

RS

$d=\sqrt{(6-(-5))^2 + (-6 - (-5))^2 }$

$d=\sqrt{11^2 + (-1)^2}$

$d=\sqrt{121 + 1}$

$d=\sqrt{122}$

d= 11.04

3 0

3 years ago