Find three consecutive even integers with a sum of 168
2 answers:
168=n+(n+2)+(n+4)
168=3n +6
168 - 6 = 3n
162/3=n
54=n
integer 1: 54
integer 2=n+2=56
integer 3=n+4=58
(x) + ( x + 2 ) + ( x + 4) = 168
3x + 6 = 168
x + 2 = 56
x = 54
so the numbers is 54, 56, 58
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