Y=-9x+10 is the equation solved for y.
Completed question:
An initial time study resulted in an average observed time of 2.2 minutes per cycle, and a standard deviation of .3 minutes per cycle. The performance rating was 1.20. What sample size, including the 20 observations in the initial study, would be necessary to have a confidence of 95.44 percent that the observed time was within 4 percent of the true value?
Answer:
47
Step-by-step explanation:
When doing a statistic study, a sample of the total amount must be taken. This sample must be done randomly, and, to be successful, the sample size (n) must be determined, by:
Where Z(α/2) is the value of the standard normal variable associated with the confidence, S is the standard deviation, and E is the precision. The confidence indicates if the study would have the same result if it would be done several times. For a confidence of 95.44, Z(α/2) = 2.
The standard deviation indicates how much of the products deviate from the ideal value, and the precision indicates how much the result can deviate from the ideal. So, if it may vary 4% of the true value (2.2), thus E = 0.04*2.2 = 0.088.
n = [(2*0.3)/0.088]²
n = 46.48
n = 47 observations.
Is there more to this question? Because there is no way to answer it.
Answer:
Using the relation between angles and sides of any triangle the answer is:
Third option: WX, XY, YW
Step-by-step explanation:
<X=90° (right angle)
<W=51°
<Y=?
The sum of the interior angles of any triangle is 180°, then:
<W+<X+<Y=180°
Replacing the given values:
51°+90°+<Y=180°
141°+<Y=180°
Solving for <Y: Subtracting 141° both sides of the equation:
141°+<Y-141°=180°-141°
<Y=39°
The order of the angles from smallest to largest is:
<Y=39°, <W=51°, <X=90°
The opposite sides to these angles must be ordered in the same way:
Opposite side to <Y: WX
Opposite side to <W: XY
Opposite side to <X: YW
Then the order of the sides from smallest to largest is:
WX, XY, YW
Answer: 1406
Step-by-step explanation:
Given Table :
Admissions Probability
1,040 0.3
1,320 0.2
1,660 0.5
Now, the expected number of admissions for the fall semester is given by :-
Hence, the expected number of admissions for the fall semester = 1406