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Kobotan [32]
3 years ago
5

Find DF to go with this problem .

Mathematics
1 answer:
pychu [463]3 years ago
3 0

Answer:

mDF = 72°

Step-by-step explanation:

<E = 1/2(160 - DF)

44 = 1/2(160 - DF)

88 = 160 - DF

DF = 160 - 88

DF = 72


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Suppose a professional golfing association requires that the standard deviation of the diameter of a golf ball be less than 0.00
Bingel [31]

Answer:

We conclude that the standard deviation of the diameter of a golf ball is less than 0.005 inch.

Step-by-step explanation:

We are given that a professional golfing association requires that the standard deviation of the diameter of a golf ball be less than 0.005 inch.

Assume that the population is normally distributed: 1.678, 1.681, 1.676, 1.684, 1.676, 1.679, 1.681, 1.681, 1.677, 1.676, 1.681, 1.683.

Let \sigma = <u><em>population standard deviation of the diameter of a golf ball.</em></u>

SO, Null Hypothesis, H_0 : \sigma \geq 0.005 inch     {means that the standard deviation of the diameter of a golf ball is more than or equal to 0.005 inch}

Alternate Hypothesis, H_0 : \sigma < 0.005 inch     {means that the standard deviation of the diameter of a golf ball is less than 0.005 inch}

The test statistics that would be used here <u>One-sample Chi-square test statistics</u>;

                            T.S. =  \frac{(n-1)s^{2} }{{\sigma^{2} }}  ~ \chi^{2} __n_-_1

where, s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 0.00281 inch

           n = sample size = 12

So, <u><em>the test statistics</em></u>  =  \frac{(12-1)\times 0.00281^{2} }{{0.005^{2} }}  ~ \chi^{2} __1_1

                                     =  3.47

The value of chi-square test statistics is 3.47.

Also, the P-value of test statistics is given by the following formula;

                P-value = P( \chi^{2} __1_1 < 3.47) = 0.0182

Since, the P-value of the test statistics is less than the level of significance as 0.0182 < 0.05, so we reject our null hypothesis.

<u>Now, at 0.05 significance level the chi-square table gives critical value of 4.575 at 11 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of chi-square as 3.47 < 4.575, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the standard deviation of the diameter of a golf ball is less than 0.005 inch.

7 0
4 years ago
Which of the following is a rational number? square root 97 square root 98, square root 99, square root 100
alexira [117]
Its D since the square root of 100 is 10

4 0
3 years ago
Read 2 more answers
Solve for k:<br> -3/5k - 1 + 1/2k = 3
ikadub [295]
The answer would be -40 c:
6 0
3 years ago
5. Write two expressions for the area of the big rectangle. ​
4vir4ik [10]

Answer:

Two expressions for the area are;

i) x/3 + 2·y + 6

ii) (1/3) × (x + 6·y + 18)

Step-by-step explanation:

The given dimension of the rectangle are;

The height of the rectangle, h = 1/3

The width of the smallest rectangle, w₁ = x

The width of the med sized rectangle, w₂ = 6·y

The width the large rectangle, w₃ = 18

The area, 'A', of the entire rectangular figure, the big rectangle, can be expressed as follows;

A = A₁ + A₂ + A₃

Where;

A₁ = The area of the smallest rectangle

A₂ = The area of the mid sized rectangle

A₃ = The area of the large rectangle

∴ A = (1/3) × x + (1/3) × 6·y + (1/3) × 18 = x/3 + 2·y + 6

The area of the big rectangle. 'A', can also be found as follows;

A = (1/3) × (x + 6·y + 18)

Therefore, two expressions for the area of the big rectangle are;

x/3 + 2·y + 6 and (1/3) × (x + 6·y + 18).

3 0
3 years ago
A sport shop has 30 employees. 80% of the employees work part time. How many part-time employees does the sports shop have?
AURORKA [14]

Answer:

they have 24 part time employees

Step-by-step explanation:

multiply 30 by .8 (which is 80% in decimal form) and you get 24. subtract that from 30 and you get 6 extra employees. 24 is the answer.

8 0
4 years ago
Read 2 more answers
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