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Yanka [14]
3 years ago
7

2 jars of spaghetti sauce $3 What is the constant poportion of this problem

Mathematics
2 answers:
fredd [130]3 years ago
7 0

1 sauce= 1.50$                   okkokokokokooaxkoofkq

Murljashka [212]3 years ago
5 0

Answer:

The constant proportion would be 1.50 for 1

Step-by-step explanation:

3/2=1.5

1.5*2=3

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A triangle and a rectangle are shown below.
nadezda [96]

Answer:

10 cm

Step-by-step explanation:

From the diagram,

Applying,

lw = 5/2(bh)..................... Equation 1

Where l = length of the rectangle, w = width of the rectangle, b = base of the triangle, h = height of the triangle.

make w the subject of the equation

w = 5(bh)/2l............... Equation 2

From the diagram,

Given: l = 12 cm, b = 6 cm, h = 8 cm

Substitute into equation 2

w = 5(6×8)/(2×12)

w = 10 cm

Hence the width of the rectangle is 10 cm

8 0
3 years ago
There’s a full 12 piece pizza. Ayla got a slice of pizza and John got 1 and two half’s of pizza.....how many slices are left.
Ghella [55]

Answer:

9

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
Jonah has a large collection of marbles he notices that if he borrows five marbles from a from a friend he can arrange the marbl
olga nikolaevna [1]

Answer:

The remainder is 8

Step-by-step explanation:

Let Jonah's Marble=x

If he arranges x marbles into y rows of 13 each, and there are remainders(R)

Then:

x/13=y+(R/13).....(I)

If he borrows 5 marbles from a friend, there will be no remainder. However, the number of rows y, will be increased by 1

New Total Marbles=x+5

(x+5)/13=y+1.....(ii)

x+5=13(y+1)

x=13y+13-5

x=13y+8

From (I)

x=13y+R

Comparing the values of x derived from (I) and (ii)

13y+R=13y+8

Therefore the Remainder, R= 8

5 0
3 years ago
UPUUVITICII
kondor19780726 [428]

Answer:

perimeter=25.12 ft

Area=50.24 ft^2

Step-by-step explanation:

Radius=4 feet

π=3.14

Perimeter=2 x π x Radius

Perimeter=2 x 3.14 x 4

Perimeter=25.12 feet

Area=π x radius x radius

Area=3.14 x 4 x 4

Area=50.24 ft^2

7 0
3 years ago
Can someone please help me
Nookie1986 [14]
Sure What do u need help with I am always here
5 0
3 years ago
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