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4 years ago

What is the property for 6 times 4 times 3= 6 times 4 times 3

Mathematics

1 answer:

inn [45]4 years ago

7 0

The multiplication property of equality, since multiplying 6 by 4 by 3 is done on the other side of the equation

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andrew-mc [135]

For the reaction,

$CO(g) + H_2 O(g) = CO_2(g) + H_2(g)$

Initial concentration:

0.1M , 0.1M , 0 , 0

Let 'x' mole per litre of each of theproduct be formed.

At equilibrium:

(0.1 – x)M , (0.1 – x)M , xM , xM

where x is the amount of Carbon dioxide and Hydrogen, at equilibrium.

Hence, equilibrium constant can be written as,

$K_c = \frac{x²}{(0.1 – x)²} = 4.24$

→ x² = 4.24 (0.01 + x² – 0.2x)

→ x² = 0.0424 + 4.24 x² - 0.848x

→ 3.24x² - 0.848x + 0.0424 = 0

a = 3.24, b = -0.848, c = 0.0424

(for quadratic equation ax² + bx+c=0)

$x = \frac{( - b \: ± \: \sqrt{ {b}^{2} - 4ac) } }{2a}$

$= > x = \frac{ - ( - 0.848 \: ± \: \sqrt{( - 0.848)^{2} - 4(3.24)(0.0424) } }{2 \times 3.24}$

$= > x = \frac{ - 0.848±0.4118}{6.48}$

$x_1 = \frac{0.848 - 0.4118}{6.48} = 0.067$

$x_2 = \frac{0.848 + 0.4118}{6.48} = 0.194$

Here, the value 0.194 should be neglected because it will give concentration of the reactant which is more than initial concentration.

∴ The equilibrium concentrations are :-

$[CO_2] [H_2] = x = 0.067M$

$[CO] [H_2 O] = 0.1 - 0.067 = 0.033M$

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3 years ago

C is the midpoint of segment AD. B is the midpoint of segment AC. BC = 12. What is the length of segment AD? *

guapka [62]

Answer:

Step-by-step explanation:

A - B - C - - - D

12 + 12 + 24 = 48

Segment B is midpoint between AC therefore the length between AB is equal to the length between BC. C is midpoint of of AD therefore the length between AB + BC is equal to the length between CD. IF AB is 12 then AB is 12. AC will be 24. Since CD is equal to AD, CD must also be 24. AD is distance AC plus CD = 48.

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docker41 [41]

Answer:

ΔDEF

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ΔCBA ≅ ΔDEF

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