The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
Must click thanks and mark brainliest
Answer:
I think its c
Step-by-step explanation:
Answer:
7 Days
Step-by-step explanation:
Miles cost:
$0.10 * 200 = $20
Daily Cost
Her budget at this point is $330 because $350 - $20 (the miles)
$330 / 42.72 = Roughly 7.72
Therefore Zoey can drive for 7 days before her budget runs out.
Option B is correct.
Step-by-step explanation:
We need to solve: ![\sqrt[3]{x^2}\sqrt[4]{x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D%5Csqrt%5B4%5D%7Bx%5E3%7D)
We know that: ![\sqrt[n]{x}\sqrt[b]{x} =\sqrt[n*b]{x.x}= \sqrt[n*b]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%5Csqrt%5Bb%5D%7Bx%7D%20%3D%5Csqrt%5Bn%2Ab%5D%7Bx.x%7D%3D%20%5Csqrt%5Bn%2Ab%5D%7Bx%5E2%7D)
Applying the above rule:
![\sqrt[3]{x^2}\sqrt[4]{x^3}\\=\sqrt[3*4]{x^2.x^3}\\=\sqrt[12]{x^5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D%5Csqrt%5B4%5D%7Bx%5E3%7D%5C%5C%3D%5Csqrt%5B3%2A4%5D%7Bx%5E2.x%5E3%7D%5C%5C%3D%5Csqrt%5B12%5D%7Bx%5E5%7D)
So, Option B is correct.
Keywords: Solving with Exponents
Learn more about Solving with Exponents at:
#learnwithBrainly
Okay, this is not really an answer, but I think in 2020, we will be in the 20 trillions. O know that is not the answer you were looking for, but its all I got.
