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2 years ago

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1/6x-4+x+3/2x+1/3=22

1 answer:

KIM [24]2 years ago

3 0

$\dfrac{1}{6}x-4+x+\dfrac{3}{2}x+\dfrac{1}{3}=22\qquad|\text{multiply both sies by 6}\\\\6\cdot\dfrac{1}{6}x-6\cdot4+6\cdot x+6\cdot\dfrac{3}{2}x+6\cdot\dfrac{1}{3}=6\cdot22\\\\x-24+6x+3\cdot3x+2=132\\\\x-24+6x+9x+2=132\\\\(x+6x+9x)+(-24+2)=132\\\\16x-22=132\qquad|\text{add 22 to both sides}\\\\16x=154\qquad|\text{divide both sides by 16}\\\\x=\dfrac{154}{16}\\\\x=\dfrac{77}{8}$

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2 years ago

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Given: 11x-6y=-1; x=8

wolverine [178]

To solve this, simply substiture 8 in for x, and solve for y.

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A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

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The new test designed for detecting TB is being analysed.

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<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

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The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

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Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

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Compute the probability that a randomly selected person is tested negative as follows:

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2 years ago

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Allushta [10]

Answer:

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Step-by-step explanation:

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2 years ago

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koban [17]

The complete question is:

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Answer:

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