Question

1/6x-4+x+3/2x+1/3=22

Answer 1

$\dfrac{1}{6}x-4+x+\dfrac{3}{2}x+\dfrac{1}{3}=22\qquad|\text{multiply both sies by 6}\\\\6\cdot\dfrac{1}{6}x-6\cdot4+6\cdot x+6\cdot\dfrac{3}{2}x+6\cdot\dfrac{1}{3}=6\cdot22\\\\x-24+6x+3\cdot3x+2=132\\\\x-24+6x+9x+2=132\\\\(x+6x+9x)+(-24+2)=132\\\\16x-22=132\qquad|\text{add 22 to both sides}\\\\16x=154\qquad|\text{divide both sides by 16}\\\\x=\dfrac{154}{16}\\\\x=\dfrac{77}{8}$