Plssss help me on this one. What’s is the interquartile range of the data?
2 answers:
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Answer:
x = -2
Step-by-step explanation:
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Answer:
A = 192 cm²
Step-by-step explanation:
Given that,
The length of the diagonal of a rectangle is 20 cm.
The difference between its length and its width is 4 cm.
Let the length is l and width is b.
ATQ,
l-b = 4 ...(1)
Let x is the diagonal of the rectangle such that,
or
....(2)
Now we need to solve equation (1) and (2).
Squaring equation (1) :
Put equation (2) in above equation.
Since, the area of the rectangle, A = lb
A = 192 cm²