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MakcuM [25]
3 years ago
10

Plssss help me on this one. What’s is the interquartile range of the data?

Mathematics
2 answers:
Natasha2012 [34]3 years ago
3 0

Answer:

The interquartile range is from 22-29

Step-by-step explanation:

Kamila [148]3 years ago
3 0

Answer: 22-27

Step-by-step explanation:

Use the numbers ranging from lower quartile (Q1), and the upper quartile (Q3)

So in this example, it would be from 22-29

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Try using the back of the book.
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3 + x + 1 = 2<br><br> Thank you :)
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Answer:

x = -2

Step-by-step explanation:

Please mark Brainliest when able, for showing work.

8 0
3 years ago
How do you dilate this function vertically by -2?
Usimov [2.4K]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Given: PSTK - trapezoid m∠P = 90°, SK=13 PK = 12, ST = 8 Find: Area of PSTK
bazaltina [42]

Answer:

Area of PSTK = 50

Step-by-step explanation:

△SPK:

SK = 13, PK = 12

13^2 - 12^2 = SP^2

SP = 5

(8 + 12) /2 x 5 = 50  


5 0
3 years ago
One of the diagonals of a rectangle a 20 cm long. The difference between its length and its width is 4 cm. Find the area of the
Dmitrij [34]

Answer:

A = 192 cm²

Step-by-step explanation:

Given that,

The length of the diagonal of a rectangle is 20 cm.

The difference between its length and its width is 4 cm.

Let the length is l and width is b.

ATQ,

l-b = 4 ...(1)

Let x is the diagonal of the rectangle such that,

x^2=l^2+b^2

or

20^2=l^2+b^2\\\\l^2+b^2=400 ....(2)

Now we need to solve equation (1) and (2).

Squaring equation (1) : l^2+b^2-2lb=16

Put equation (2) in above equation.

400-2lb=16\\\\400-16=2lb\\\\2lb=384\\\\lb=192

Since, the area of the rectangle, A = lb

A = 192 cm²

8 0
3 years ago
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