How many eight-digit numbers can be formed if the leading digit cannot be zero and the last number cannot be 1 ?
1 answer:
Answer:
128 unique numbers
Step-by-step explanation:
Since only 0 and 1 are to be used, an 8 digit number will have a leading 1. The rest 7 places are free to be either 0 or 1
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Answer: 3000 multiplied by 0.05
and u get you get the 0.05 by dividing 5 by 100.
Step-by-step explanation:
Y= -9x
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8
hope this helps
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Question 4 is (1,2)
Question 5 is (1,0)
These are are definitely correct
Answer: I don't know
Step-by-step explanation:
Here is the set up:
(1/4)/2 = (9/4)/y
Solve for y.
