Answer:
d^2 - π(d/2)^2
Step-by-step explanation:
Since the diameter of the circle is equal to the side of a square (d), that means that we have a circle inscribed in square.
If we draw a square and inscribe a circle in it, all parts of the square outside the circle will be waste, in this particular case.
If we want to find the area of the wasted material we need to subtract the area of the circle from the area of the square.
Area of the circle is:
P1 = πr^2, r being the radius
Since radius is half the diameter, that means that:
P1 = π • (d/2)^2
Area of the square whose side is d is:
P2 = d^2
So, the area of wasted material is:
P = P2 - P1
P = d^2 - π(d/2)^2
Answer:
cannot
not constant
Step-by-step explanation:
1st rate of change is 5 - (-1) / 4 - 2 = 6 / 2 = 3
2nd rate of change is 15 - 5 / 6 - 4 = 10 / 2 = 5
3rd rate is 29 - 15 / 8 - 6 = 14 / 2 = 7
cannot be modeled into a linear equation
rate of change is not constant
Answer:
i dont know
Step-by-step explanation:
Answer:
x-intercept: (-3,0)
y-intercept: (0,-3)
Step-by-step explanation:
Looking at the equation, we can see that it is already in standard form, or in a 
format. Whenever a line is put into standard form, the x-intercepts are represented by 
and the y-intercepts are represented by 
. So, let's calculate them by doing the following:
1) Find the x-intercept by using the formula. Substitute the number on the right side of the equation for 
and the coefficient for the x term for 
. So, in this case, 
and 
:
Therefore, the x-intercept is (-3,0).
2) Next, find the y-intercept by using the 
formula and substituting the right values. is still the number on the right side of the equation and 
is the coefficient of the y term. So, and 
.
Therefore, (0, -3) is the y-intercept.
