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3 years ago

13

Andrew drove 55 mph on his trip. Which of the following equations best represents the distance he drove if x stands for the numb

er of hours?

2 answers:

sergejj [24]3 years ago

5 0

55*x
X= The hours
I hope this helps!!

Luda [366]3 years ago

5 0

Answer

Using speed formula:

$\text{Speed} = \frac{\text{Distance}}{\text{Time}}$

Let y represents the distance in miles and x represents the time in hours.

As per the given statement:

Andrew drove 55 mph on his trip.

Using formula;

we have;

$55 = \frac{y}{x}$

Multiply both sides by x we have;

$y = 55x$

Therefore, the equation best represents the distance he drove is $y = 55x$

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Five whole numbers are written in order

jeka57 [31]

Answer:

x=7

y=8

Step-by-step explanation:

-Given that the mean and median is the same.

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#Given that the set is arranged in order and is even:

$median=\frac{n+1}{2}\\\\Median=3^{rd} \ term\\\\=x$

Hence:

$b=median=mean\\\\b=x\\\\\therefore mean=median=x$

-Applying the mean formula:

$\bar x=\frac{1}{n}\sum{x_i}\\\\\therefore 5x=4+6+x+y+10\\\\4x=20+y\\\\x=5+0.25y$

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3 years ago

If f(x) = -7x + 5x2 + 10, what does f(-2) equal?

aksik [14]

Answer:

f(-2) = 44

Step-by-step explanation:

Hello there! Lets get started solving this function!

For a function, whenever we see f(x) = ... , the function is simply asking the value of the equation at x! So, if replace f(x) with f(-2), we simply substitute x with -2 in the equation! Lets get started!

$f(x) = -7x + 5x^{2} + 10\\f(-2) = -7(-2) + 5(-2)^{2} + 10\\f(-2) = 14 + 20 + 10\\f(-2) = 44\\$

First, we can write the original function. Next, we substitute in -2 for x. Then, we find our final terms. Finally, we are given that f(-2) = 44.

Hope this helps! Remember, math is fun!

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3 years ago

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

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$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

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