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Alexxandr [17]
2 years ago
5

A quadrilateral has exactly 3 congruent sides, someone thinks it is a rectangle, why is that someone wrong?

Mathematics
1 answer:
Umnica [9.8K]2 years ago
5 0

Answer:

It is because a rectangle has 4 congruent sides.

A rectangle has 4 congruent sides since it has four 90 degrees sides, its corners. This someone say a shape with 3 congruent sides is a rectangle.

This is why it is wrong.

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USPshnik [31]
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7 0
2 years ago
The following are the last 7 days adjusted closing stock prices (in $) for Citigroup: 22, 25, 20, 15, 40, 55, 28 A) Compute the
son4ous [18]

Answer:

(A) The 25th percentile is 20.

(B) The mean of the data set is 20 and the median of the data set is 25. The data set is left-skewed.

Step-by-step explanation:

The data set arranged in ascending order is:

S = {15, 20, 22, 25, 28, 40, 55}

(A)

Compute the 25th percentile as follows:

25^{th} \text{Percentile}=[\frac{n+1}{4}]^{th}obs.\\\\=[\frac{7+1}{4}]^{th}obs.\\\\=2^{nd}obs.\\\\=20

Thus, the 25th percentile is 20. This value implies that exactly 25% of the observations are less than 20.

(B)

Compute the sample mean as follows:

\text{Mean}=\frac{22+25+20+15+40+55+28}{7}=\frac{205}{7}=29.29

Compute the median as follows:

For a set with odd number of observations, the median value if the middle value.

The middle value is 25.

Thus, the mean of the data set is 20 and the median of the data set is 25.

The Mean < Median.

This implies that the data set is left-skewed.

4 0
2 years ago
Subtract 8 from n then divide m by the result
Likurg_2 [28]

What exactly is n? I need to know n so I can figure out m.

4 0
3 years ago
A side of the triangle below has been extended to form an exterior angle of 159º. Find the value of x.
xenn [34]

Answer:

x = 69

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles in a triangle

x+90 = 159

Subtract 90 from each side

x +90-90 = 159-90

x =69

5 0
3 years ago
Read 2 more answers
The quadratic formula gives which roots for the equation 2x^2 + x - 6 = 0?
Jet001 [13]

Answer:

The roots are x = (\frac{3}{2}, -2), which is given by option C.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question, we have that:

2x^2 + x - 6 = 0

Which is a quadratic equation with a = 2, b = 1, c = -6. So

\Delta = 1^{2} - 4*2(-6) = 1 + 48 = 49

x_{1} = \frac{-1 + \sqrt{49}}{2*2} = \frac{6}{4} = \frac{3}{2}

x_{2} = \frac{-1 - \sqrt{49}}{2*2} = \frac{-8}{4} = -2

So the roots are x = (\frac{3}{2}, -2), which is given by option C.

3 0
3 years ago
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