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just olya [345]
3 years ago
5

A company paid $48 for 2 cases of printer paper. each case contained 12 packages of paper. next month the company’s office manag

er needs to order 180 packages of the same paper. if the price per package does not change, what would be the total cost of next month’s order?
Mathematics
1 answer:
enyata [817]3 years ago
6 0
Cost would be $4,320.
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the performing arts department put in its spring show on Friday and Saturday nights. the price of a ticket was the same both nig
Galina-37 [17]
Let p= the price of a ticket
Let c= the cost to put on the show

Formula:
(profit) = (ticket price) * (number of people) - (cost to put on show)
We have two equations here:
500=120p-c
400=100p-c
Solve:
100=20p
⇒p=5
⇒400=100(5)-c
⇒400=500-c
⇒c=100

So the price of a ticket is $5, and the cost to put on the show is $100.
3 0
3 years ago
What is 3/6 as a decimal?
iren2701 [21]
0.5 is the answer hope I helped you
5 0
3 years ago
Can somebody explain to me how they got 3^4(x) = 3^3(x+2)? Then explain what happened to the 3 in 3^4 and the 3 in 3^3? Please a
musickatia [10]

Answer:

x=6

Step-by-step explanation:

81^x = 27 ^(x+2)

81 = 3^4    and 27 =3^3  so replace 81 and 27 in the equation

3^4^x = 3^3^(x+2)

When we have a power to a power we can multiply the exponents

a ^b^c = a^(b*c)

3^(4x) = 3^(3*(x+2))

Since the bases are the same, the exponents  have to be the same

a^b = a^c   means b=c

4x = 3(x+2)

Now we can solve for x

Distribute

4x = 3x+6

Subtract 3x from each side

4x-3x = 3x-3x+6

x = 6

3 0
3 years ago
Find the measure of each angle.
Feliz [49]

Answer:

I mite be rong but I think 8x and 3x

6 0
3 years ago
Lucy is using a one-sample t ‑test based on a simple random sample of size n = 22 to test the null hypothesis H 0 : μ = 16.000 c
slega [8]

Answer:

The value of test statistic is 1.338

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 16.000

Sample mean, \bar{x} = 16.218

Sample size, n = 22

Alpha, α = 0.05

Sample standard deviation, s = 0.764

First, we design the null and the alternate hypothesis

H_{0}: \mu = 16.000\text{ cm}\\H_A: \mu < 16.000\text{ cm}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{16.218 - 16.000}{\frac{0.764}{\sqrt{22}} } = 1.338

Thus, the value of test statistic is 1.338

4 0
3 years ago
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