Isaac is constructing a circular pool that has a diameter of 20 ft and is 5 ft deep. Part A: Find the circumference of the pool to the nearest tenth of a foot. Use 3.14 for pi. Part B: Find the area of the circle formed by the pool to the nearest foot.
1 answer:
Answer:
The circumference of the pool is 62.8 foot long and the area of the circle formed by the pool is 314 ft².
Step-by-step explanation:
The circumference of the pool can be found by calculating the arc's length of the edges of the pool. This is done by using the following formula:
Where the radius is half the diameter, applying the data from the problem we have:
The area of the circle formed by the pool can be found using the following expression:
The circumference of the pool is 62.8 foot long and the area of the circle formed by the pool is 314 ft².
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Answer:
12 cm
Explanation:
From
Pythagoras Theorem
h
2
=
a
2
+
b
2
where
h =
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a =
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b =
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(
20 cm
)
2
=
(
16 cm
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2
+
b
2
b
2
=
(
20 cm
)
2
−
(
16 cm
)
2
b
=
√
(
20 cm
)
2
−
(
16 cm
)
2
b
=
√
400 cm
2
−
256 cm
2
b
=
√
144 cm
2
b = 12 cmStep-by-step explanation:
Answer:
B ; A
Step-by-step explanation:
1) The first operation that we have to do is the division
2) we have to added up the the fishes
