Question

Find tan^-1 1.4826 to the nearest degree

Answer 1

Answer:

A= 131 degrees 3 min or

A = 311 deg 3 min

Step-by-step explanation:

Given is a value -1.14826

We have to find the angle such that

tan A= -1.14826

We know that tangent is negative in II and IV quadrant.

Hence angle A should lie in II or IV quadrant.

First find B such that

tan B =1.14826(removing negative sign)

$B=48.95 =48 degree 57 min$

Hence $A =180-B : A=360-BA=131.05 : A=311.05$

Answer 2

Answer is 56.00 degree