If the perimeter of a rectangle is expressed by 2x^2+5x+9 and the width is 2x^2+1, find an expression for the length.
1 answer:
Answer:
-x^2+5/2x+7/2 = L
Step-by-step explanation:
We know the perimeter of a rectangle is given by
P = 2(L + W)
Substitute what we know
2x^2+5x+9 = 2( L+ 2x^2+1)
Distribute
2x^2+5x+9 = 2 L+ 4x^2+2
Subtract 4x^2 from each side
2x^2-4x^2+5x+9 = 2 L+ 4x^2-4x^2+2
-2x^2+5x+9 = 2 L+2
Subtract 2 from each side 2 from each side
-2x^2+5x+9-2 = 2 L+2-2
-2x^2+5x+7 = 2 L
Divide each side by 2
-2/2x^2+5/2x+7/2 = 2 L/2
-x^2+5/2x+7/2 = L
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Answer:
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Answer:
4:9
Step-by-step explanation:
To take the scale factor from distance to area, we square it
2:3 distance
Square each term
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4:9
Parent function: y =x3 ; shift
4 units to the left
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