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Alik [6]
3 years ago
14

Can someone help me with this question please.

Mathematics
2 answers:
kifflom [539]3 years ago
8 0
The answer would most defiantly be “21”, choice c “21”
photoshop1234 [79]3 years ago
8 0

Answer:

21

Step-by-step explanation:

The formula for triangular numbers is n×(n+1)÷2 (n is the step of next number)

we have 1, 3, 6, 10, 15 so the next step would be 6th

6×(6+1)÷2 = 21

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Find the limit
Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

\large\underline{\sf{Solution-}}

Given expression is

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

On substituting directly x = 1, we get,

\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}

\rm \: = \sf \: \: - \infty \: - \: \infty

which is indeterminant form.

Consider again,

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

can be rewritten as

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]

\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}

\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}

\rm \: = \: \sf \boxed{2}

Hence,

\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}

\rule{190pt}{2pt}

7 0
3 years ago
Read 2 more answers
Lucia has 3.5 hours left in her workday as a car mechanic. Lucia needs 1/2 of an hour to complete one oil change.
MatroZZZ [7]

Answer: So Lucía has 3.5 hours left, and need 1/2 of an hour (or 0.5 hours) to do one oil change.

a) If you divide the total time she has by the time she needs for each oil change, then you got the total number of oil changes that she can do in that time; this is:

3.5/0.5 = 7

So she can do 7 oil changes in 3.5 hours.

b) If she can complete two car inspections in the same amount of time it takes her to complete one oil change, then she can do two car inspections in 0.5 hours.

2*car inspections = 0.5 hours

car inspection = (0.5/2) hours

then one car inspection will take 0.5/2 = 0.25 hours.

c) Two ways to solve this:

1) Do the same that we did in a), this is: 3.5/0.25 = 14

she can do 14 car inspections.

2) If in 3.5 hours, she can do 7 oil changes, and in the time she does an oil change, she can do two car inspections, then in 3.5 hours she can do 7*2 car inspections, and 7*2 = 14

5 0
3 years ago
Read 2 more answers
Please help me i don't know what else to put here.........................
Pepsi [2]
ANSWERRR
1. 15%
2.20%
3.45%
3 0
3 years ago
you eat 3/10 of a coconut your friend eats 1/5 of the coconut what fraction of the coconut do you have and your friend eat write
Bas_tet [7]

Answer:

I eat 3/10 of the coconut and my friend eats 1/5 which is 2/10.

We both eat 3/10 + 2/10 which is 1/2 of the coconut.

7 0
3 years ago
X to the 5th times x to the 7a​
Leya [2.2K]

Answer:

(x^5)(x^7)

Step-by-step explanation:

6 0
3 years ago
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