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Alik [6]
4 years ago
14

Can someone help me with this question please.

Mathematics
2 answers:
kifflom [539]4 years ago
8 0
The answer would most defiantly be “21”, choice c “21”
photoshop1234 [79]4 years ago
8 0

Answer:

21

Step-by-step explanation:

The formula for triangular numbers is n×(n+1)÷2 (n is the step of next number)

we have 1, 3, 6, 10, 15 so the next step would be 6th

6×(6+1)÷2 = 21

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What is the solution to the equation? 4x - 8 = 16<br>need this at least by tomorrow!<br>thank you!​
Gelneren [198K]

Answer:

x = 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

4x - 8 = 16

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 8 to both sides:                    4x = 24
  2. Divide 4 on both sides:               x = 6

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                   4(6) - 8 = 16
  2. Multiply:                              24 - 8 = 16
  3. Subtract:                             16 = 16

Here we see that 16 does indeed equal 16.

∴ x = 6 is the solution to the equation.

5 0
3 years ago
Read 2 more answers
5. A markup of 30% on cost is equivalent to a 41% markup on selling price,<br> True<br> False
aivan3 [116]

Answer:

false

Step-by-step explanation:

cost and selling price are the same thing so there would be no difference in percentage

8 0
3 years ago
The graph of g(x) = -x^2 is shifted 3 units left and 1 unit up. If this new graph is f(x), then what is the value of f(-1.5)
kondor19780726 [428]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;% left side templates&#10;\begin{array}{llll}&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}\\\\&#10;--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see.

to the left by 3 units, C = +3
up by 1  unit, D = 1

\bf g(x)=-x^2\\\\\\ g(x)=-1(1x+\stackrel{C}{0})^2+\stackrel{D}{0}\implies g(x)=-1(1x+3)^2+1&#10;\\\\\\&#10;g(x)=-(x+3)^2+1\impliedby f(x)\qquad \qquad f(-1.5)=-[(-1.5)+3]^2+1

and surely you know how much that is.
5 0
4 years ago
This table shows the top athletes that play both football and basketball. What is the intersection of the set of football player
Yuki888 [10]

Answer:

the answer is  {Corelli, Yao}

Step-by-step explanation:

i took the quiz

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3 years ago
Combine like terms in the expression below. <br><br><br>5c + 6 + 8c - 2<br><br>Plz help
Eva8 [605]
Answer:
13c+6-2

Explanation:
You combine the amount of cs with each other.
8 0
3 years ago
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