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skad [1K]
3 years ago
11

HELP PLS! THANK YOU SO MUCH! Consider the quadratic equation 3x^2-6=2x. (a) What is the value of the discriminant? (b) What does

the discriminant of the quadratic equation tell about the solutions to 3x^2-6=2x
Mathematics
1 answer:
ivanzaharov [21]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

Given a quadratic equation in standard form, ax² + bx + c = 0 ( a ≠ 0 )

Then the discriminant Δ = b² - 4ac informs us about the nature of the roots.

• If b² - 4ac > 0 then 2 real and distinct roots ( solutions )

• If b² - 4ac = 0 then 2 real and equal roots

• If b² - 4ac < 0 then roots are not real

Given

3x² - 6 = 2x ( subtract 2x from both sides )

3x² - 2x - 6 = 0 ← in standard form

with a = 3, b = - 2, c = - 6 , thus

b² - 4ac = (- 2)² - ( 4 × 3 × - 6) = 4 - (- 72) = 4 + 72 = 76

Since b² - 4ac > 0 then the solution is 2 real and distinct roots

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Perimeter<br>pi = 22/ 7 any help? ​
MrMuchimi

Step-by-step explanation:

I) 9+9+9+9=36

Ii)radius is 4.5 L=2piR= 2pi(4.5)= 9pi

Iii) A=piR^2= pi(4.5)^2 = 20.5pi

IV) 9×9 =81

V) 81-20.5pi = 16.597

6 0
3 years ago
Read 2 more answers
What is the product? Assume x greater-than-or-equal-to 0 (StartRoot 3 x EndRoot + StartRoot 5 EndRoot) (StartRoot 15 x EndRoot +
OlgaM077 [116]

Answer:

3\sqrt5 x+ \sqrt x (6 \sqrt{10} +5\sqrt{3}) +10 \sqrt6

Step-by-step explanation:

To find the product :

(\sqrt{3x} +\sqrt5)(\sqrt{15x} +2\sqrt{30})

\sqrt{3x}(\sqrt{15x} +2\sqrt{30}) +\sqrt5(\sqrt{15x} +2\sqrt{30})\\\Rightarrow \sqrt{3x}\times \sqrt{15x} +\sqrt{3x}\times 2\sqrt{30} +\sqrt5 \times \sqrt{15x} +\sqrt5\times 2\sqrt{30}\\\Rightarrow \sqrt{45} \times x + 2 \sqrt{90x} + \sqrt{75x} + 2 \sqrt{150}\\\Rightarrow \sqrt{5 \times 9} \times x + 2 \sqrt{9\times 10x} + \sqrt{25 \times 3x} + 2 \sqrt{25 \times 6}\\\Rightarrow 3\sqrt5 x+ 2 \times 3 \sqrt{10x} +5\sqrt{3x} +2 \times 5 \sqrt6\\\Rightarrow 3\sqrt5 x+ 6 \sqrt{10x} +5\sqrt{3x} +10 \sqrt6

\Rightarrow 3\sqrt5 x+ \sqrt x (6 \sqrt{10} +5\sqrt{3}) +10 \sqrt6

Some identities used:

1. (a+b)(c+d) = a (c+d) + b(c+d)

2. \sqrt9  =3

3. \sqrt{25}  =5

4. \sqrt x \times \sqrt x=x

5. \sqrt a \times \sqrt b = \sqrt{ab}

So, the solution is 3\sqrt5 x+ \sqrt x (6 \sqrt{10} +5\sqrt{3}) +10 \sqrt6

8 0
3 years ago
Read 2 more answers
Help me find What is 52÷8
leonid [27]
6.5 is the answer. You can check by 6.5x8=52
5 0
3 years ago
9.
e-lub [12.9K]

Answer:

a = 0.3 and b = - 1.1

Step-by-step explanation:

(x - 2)² = x² -4x + 4

Hence, x² - 4x + 4 = 3x - 6

x² - 7x + 10 = 0

(x - 5)(x - 2) = 0

∴ x = 5 or 2

f(5) = 25a + 5b = 2  ----- (i)

f(2) = 4a +  2b = -1  ------ (ii)

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(ii) X 5: 20a + 10a = -5  ---- (iv)

Subtract (iv) from (iii): 30a = 9

a = 0.3

Substitute a into (ii) to obtain b

4(0.3) + 2b = -1

2b = -1 - 1.2 = -2.2

∴ b = -1.1

8 0
3 years ago
A The integer with the greatest value is the one that has the greatest absolute value.
pentagon [3]

Answer: B The integer with the greatest value is one that is farthest from zero on the number line.

Step-by-step explanation: hope it correct :D

5 0
3 years ago
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