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snow_tiger [21]
3 years ago
9

Which BI tool or technique would be most useful in predicting the likelihood of a fire in a building? a. Data mining b. Dashboar

ds c. Simple linear regression d. Drill-down analysis on the building data
Computers and Technology
1 answer:
Ratling [72]3 years ago
4 0

Answer: Data Mining

Explanation: Making prediction on the likelihood or occurrence of an event in the area of business intelligence often requires gathering large volume of data which are useful in making such prediction. However, these datasets required for making prediction on events such as fire outbreak are usually unlabeled, therefore, making inference or prediction from such data require intelligent techniques capable of generating hidden patterns and relationships in the data. The act of uncovering hidden patterns in large volumes of data is usually called DATA MINING. data mining usually employs concept of machine learning, statistics and artificial intelligence using relevant and powerful algorithms such as clustering in generating insight from these datasets. Dashboards are used for visualizing and creating a pictorial output of events or analysis. While simple linear regression are used on numeric and labeled data.

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C. is the correct answer
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Write a lottery program that will ask the user if they would like to pick 5 numbers (1-30) or if they would like to choose EZ Pi
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Answer:

Explanation:

The following code is written in Python and creates arrays for the user's numbers and the next chance numbers, it also creates a cost variable and a did_you_win variable. The function takes in the winning numbers as an array parameter. It asks all the necessary questions to generate data for all the variables and then compares the user's numbers to the winning numbers in order to detect if the user has won. Finally, it prints all the necessary information.

import random

def lottery(winning_numbers):

   user_numbers = []

   next_chance_drawing = []

   cost = 0

   did_you_win = "No"

   #print("Would you like to choose your own 5 numbers? Y or N")

   answer = input("Would you like to choose your own 5 numbers? Y or N: ")

   if answer.capitalize() == "Y":

       for x in range(5):

           user_numbers.append(input("Enter number " + str(x+1) + ": "))

   else:

       for x in range(5):

           user_numbers.append(random.randint(0,31))

           cost += 1

   next_chance = input("Would you like to enter a Next Chance drawing for $1.00? Y or N: ")

   if next_chance.capitalize() == "Y":

       for x in range(4):

           next_chance_drawing.append(random.randint(0, 31))

           cost += 1

           

   if user_numbers == winning_numbers or next_chance_drawing == winning_numbers:

       did_you_win = "Yes"

   print("User Numbers: " + str(user_numbers))

   print("Next Chance Numbers: " + str(next_chance_drawing))

   print("Cost: $" + str(cost))

   print("Did you win: " + did_you_win)

6 0
2 years ago
Business customers pay $0.006 per gallon for the first 8000 gallons. If the usage is more than 8000 gallons, the rate will be $0
trasher [3.6K]

Answer:

#include <bits/stdc++.h>

using namespace std;

int main()

{

   // variables

   char cust_t;

   int no_gallon;

   double cost=0;

   cout<<"Enter the type of customer(B for business or R for residential):";

   // read the type of customer

   cin>>cust_t;

   // if type is business

   if(cust_t=='b'||cust_t=='B')

   {

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.006;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {

           // if number of gallons is greater than 8000

           // calculate cost

           cost=(8000*0.006)+((no_gallon-8000)*0.008);

           cout<<"total cost is: $"<<cost<<endl;

           

       }

       

   }

   

   // if customer type is residential

   else if(cust_t=='r'||cust_t=='R')

        {

           

       cout<<"please enter the number of gallons:";

       // read the number of gallons

       cin>>no_gallon;

       // if number of gallons are less or equal to 8000

       if(no_gallon<=8000)

       {

           // calculate cost

           cost=no_gallon*0.007;

           cout<<"total cost is: $"<<cost<<endl;

       }

       else

       {// if number of gallons is greater than 8000

       // calculate cost

           cost=(8000*0.005)+((no_gallon-8000)*0.007);

           cout<<"total cost is: $"<<cost<<endl;      

       }        

   }

return 0;

}

Explanation:

Ask user to enter the type of customer and assign it to variable "cust_t". If the customer type is business then read the number of gallons from user and assign it to variable "no_gallon". Then calculate cost of gallons, if  gallons are less or equal to 800 then multiply it with 0.006.And if gallons are greater than 8000, cost for  first 8000 will be multiply by 0.006 and  for rest gallons multiply with 0.008.Similarly if customer type is residential then for first 8000 gallons cost will be multiply by 0.005 and for rest it will  multiply by 0.007. Then print the cost.

Output:

Enter the type of customer(B for business or R for residential):b                                                                                            

please enter the number of gallons:9000                                                                                                                      

total cost is: $56  

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Answer:

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Explanation:

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Answer:

see explaination

Explanation:

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result = ""

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