Answer:
Height of this missing bar would be 1
Step-by-step explanation:
Since there is 1 and only 1 quantity between 80-99.
Answer:
W=5
Step-by-step explanation:
W=Width=Length + 1
L = Length
Area = Length * Width = 20
Area = L * W = L * (L+1) = 20
Distribute the L: L^2 + L = 20
Subtract 20 from both sides: L^2 + L -20 = 20-20
Simplify: L^2+L-20=0
Factor (L-4)(L+5)=0
Solve using the zero property: L-4=0, L=4 L+5=0, L=-5
The two options for length are 4 and -5. Only 4 will work for L since it cannot be negative. Width is Length + 1 = 5
Answer:
31.4 inches
Step-by-step explanation:
If a circle is inscribed in a square then diameter of circle inscribed is same as side as of square.
In the given problem it is given that side of square is 10 inches.
So diameter of circle inscribed is 10 inches
we know radius of circle is half of diameter of circle
Thus, radius of circle inscribed = diameter of circle/2 = 10/2 = 5inches.
Expression to calculate circumference of circle is given by 
where r is the radius of circle.
Thus circumference of circle inscribed is

Thus, circumference of circle inscribed is 31.4 inches
Answer:
If 5x-2 = 3x+4, then x=3
Step-by-step explanation:
5x-2=3x+4
Add 2 to both sides, and you get 5x=3x+6. Subtract 3x from both sides, and you get 2x=6. Divide both sides by 2, and what's left is x=3. Hope this helps. :)
Answer:
Step-by-step explanation:
This is simply a units conversion problem. It gives us for the number of passengers, the number of seats per carriage and the number of carriages per train. To change the units from passengers to trains without changing the value, we use the multiplicative identity (that is, 1).
350000 passengers
(350000 passengers) * 1
(350000 passengers) * ((1 carriage)/(32 passengers)) * ((1 train)/(15 carriages)
[note: passengers and carriages cancel. Leaving only trains]
(350000)*(1/32)*(1/15) trains [note: I write this way to paste into MS Excel]
729.1667 trains [oh, but don’t just round this number either up or down]
729 full trains can carry 729*32*15 = 349920 passengers
730 full trains can carry 730*32*15 = 350400 passengers
Now, we can say that 730 trains are adequate to carry 350000 passengers.