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2 years ago

Find the slope of a line that passes through (-4,-5) and (-3,5)

Mathematics

1 answer:

Nutka1998 [239]2 years ago

6 0

Answer:

Step-by-step explanation:

Slope m = y2 - y1/ x2- x1

( kindly note the numerals written are subscripts)

From question;

(-4, -5) = (x1, y1)

(-3,5) = ( x2, y2)

Slope m = 5-(-5) / (-3) - (-4)

Slope m = 5+5/ -3 + 4

Slope m = 10/ 1

Slope m = 10

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How do I simplify the square root: 7 times the square root of 81

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7. Cindy is paid $7.00 an hour for a regular 35-hour week. She receives overtime pay

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2 years ago

A rectangular-shaped school courtyardhas a length of 280 feet and a width of150 feet wide. What is the approximatelength of a di

UNO [17]

Answer:

317.6 feet

Step-by-step explanation:

the length of the diagonal can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c = hypotenuse

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the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero

317.6 to the nearest tenth

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2 years ago

Which of the following is equal to √16x4?<br> A. 32 B. 64 C. √16/4 D. √16•√4

Varvara68 [4.7K]

Answer:

none

Step-by-step explanation:

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2 years ago

Read 2 more answers

Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa

Artyom0805 [142]

Answer:

The height of the right trapezoid is $\frac{6}{5+\sqrt{3}}\ units$

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+DH+HA$

we have

$P=6\ units$

$AB=BC=CH=HA=x$ ---> because is a square

substitute

$6=x+x+CD+DH+x$

$6=3x+CD+DH$ -----> equation A

<em>In the right triangle CDH</em>

$sin(30\°)=\frac{CH}{CD}$

$sin(30\°)=\frac{1}{2}$

Remember that $CH=x$

$\frac{1}{2}=\frac{x}{CD}$

$CD=2x$

$tan(30\°)=\frac{CH}{DH}$

$tan(30\°)=\frac{\sqrt{3}}{3}$

$\frac{\sqrt{3}}{3}=\frac{x}{DH}$

$DH=x\sqrt{3}$

substitute the values in the equation A

$6=3x+CD+DH$ -----> equation A

$CD=2x$

$DH=x\sqrt{3}$

$6=3x+2x+x\sqrt{3}$

$6=5x+x\sqrt{3}$

$6=x[5+\sqrt{3}]$

$x=\frac{6}{5+\sqrt{3}}\ units$

5 0

2 years ago