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Solnce55 [7]
2 years ago
14

Mr. Menedez ran 13.1 miles at a constant rate for 150 minutes. To find how fast he ran, you solve the equation 13.1 = x • 150. W

hat does x represent?
Mathematics
2 answers:
Sauron [17]2 years ago
7 0

x represents the miles per minute.

This is because distance is always found by

rate x minutes

Phoenix [80]2 years ago
4 0

Answer: x = represents the miles per minute.

Step-by-step explanation:

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Explain the differences between properties of equality
Arisa [49]

Step-by-step explanation:

step 1. properties of equality have an "=" in the equation.

step 2. properties of inequality have a <, <=, >=, or a >.

8 0
3 years ago
how many feet are in 3.2km given that 1 mile is 1.609km and 1 mile 5280.A. 2654.85ft B. 8495.52ft C. 9437.42ft D. 10500.93ft
LuckyWell [14K]

Answer:

3.2 km * 1 / 1.609 mi / km * 5280 ft / mi = 10,501 ft

Check:    3280.84 ft / km * 3.2 km = 10,499 ft

5 0
3 years ago
MODELING WITH MATHEMATICS A farmer plants a garden that contains corn and pumpkins. The total area (in square
laiz [17]

Answer:

The equation in standard form that models area of pumpkins is:

A_p = A_G - A_c

and the area is: x^2+8x+2

Step-by-step explanation:

Given that the garden has corn and pumpkins

The expressions are:

Total area of garden: A_G = 2x^2+5x+4

Area of Corn: A_c = x^2-3x+2

Area of Pumpkins: A_p = ?

The sum of areas of corn and pumpkins is the total area of the garden.

It can be expressed mathematically as:

A_G = A_c+A_p

If we have to find the area of pumpkins,

A_p = A_G - A_c

Putting the values

A_p = (2x^2+5x+4) - (x^2-3x+2)\\A_p = 2x^2+5x+4-x^2+3x-2\\A_p = 2x^2-x^2+5x+3x+4-2\\A_p = x^2+8x+2

The equation in standard form that models area of pumpkins is:

A_p = A_G - A_c

and the area is: x^2+8x+2

3 0
2 years ago
Plz Help .............​
Rus_ich [418]

363.9ft^{2}

Step-by-step explanation:

Area =\pi r^{2} -\frac{1}{3}\pi r^{2}  +\frac{1}{2}r^{2}sin\alpha \\\\\\   = \frac{2}{3}\pi 12^{2} +\frac{1}{2}12^{2}sin120 =363.9ft^{2}

5 0
3 years ago
Read 2 more answers
A kitchen drawer has a Volume 1,125 cubic inches. The drawer is 15 inches long and 5 inches deep. What is the width of the drawe
Temka [501]

Answer:

The width of the drawer is 15\ in

Step-by-step explanation:

we know that

The volume of the drawer is equal to

V=LWH

we have

L=15\ in

H=5\ in -----> the deep of the drawer

V=1,125\ in^{3}

substitute the given values in the formula and solve for W

1,125=(15)(W)(5)

1,125=(75)(W)

W=1,125/(75)

W=15\ in

7 0
3 years ago
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