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kramer
3 years ago
6

If I have 40 pieces of candy and I sell them all for $20 how much would each piece of candy be worth

Mathematics
1 answer:
Hatshy [7]3 years ago
5 0

Answer:

2cents

Step-by-step explanation:

40/20=2

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The​ _____ _____, denoted ModifyingAbove p with caretp​, is given by the formula ModifyingAbove p with caretpequals=​_____, wher
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Answer:

The​ <u>sample proportion</u>, denoted by  ^p​, is given by the formula ^p=​ \frac{x}{n}, where x is the number of individuals with a specified characteristic in a sample of n individuals.

Step-by-step explanation:

Sample proportion is used to determine sample mean, sample standard error and test the hypotheses about the population.

<em>sample mean</em> can be stated as p and <em>sample standard error</em> can be found using the equation\sqrt{\frac{p*(1-p)}{n} } where

  • n is the sample size
  • p is the sample proportion

And if n×p×(1-p)≥10, then sample is assumed large enough to assume normal distribution and apply statistical test.

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3 years ago
What is the solution to the inequality 5.25 – b ≥ 6.5?
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- b \geqslant 6.5 - 5.25 \\

b \leqslant 1.25

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3 years ago
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Alexis and tara both mine salt. alexis mines 300 pounds in 20 hours. tara mines 400 pounds in 40 hours. which of the following i
Archy [21]
Well, if both Alexis and Tara mine salt for 40 hours... they'd have mine 1,000 pounds of salt. Is this what you were looking for?
7 0
2 years ago
So I have zero over five and we are doing something or some form in class and I have no idea what the answer will be
faltersainse [42]

Answer:

0

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8 0
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QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
Andru [333]

Answer:

(a)Revenue=580x-10x²,

Marginal Revenue=580-20x

(b)Fixed Cost, =900

Marginal Cost,=300+50x

(c)Profit Function=280x-900-35x²

(d)x=4

Step-by-step explanation:

The price, p = 580 − 10x where x is the number of cakes sold per day.

Total cost function,c = (30+5x)²

(a) Revenue Function

R(x)=x*p(x)=x(580 − 10x)

R(x)=580x-10x²

Marginal Revenue Function

This is the derivative of the revenue function.

If R(x)=580x-10x²,

R'(x)=580-20x

(b)Total cost function,c = (30+5x)²

c=(30+5x)(30+5x)

=900+300x+25x²

Therefore, Fixed Cost, =900

Marginal Cost Function

This is the derivative of the cost function.

If c(x)=900+300x+25x²

Marginal Cost, c'(x)=300+50x

(c)Profit Function

Profit, P(x)=R(x)-C(x)

=(580x-10x²)-(900+300x+25x²)

=580x-10x²-900-300x-25x²

P(x)=280x-900-35x²

(d)To maximize profit, we take the derivative of P(x) in (c) above and solve for its critical point.

Since P(x)=280x-900-35x²

P'(x)=280-70x

Equate the derivative to zero

280-70x=0

280=70x

x=4

The number of cakes that maximizes profit is 4.

5 0
2 years ago
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