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MrRa [10]
2 years ago
7

What is 221,000,000,000,000,000,000 expressed in scientific notation?

Mathematics
2 answers:
Fiesta28 [93]2 years ago
8 0
Your answer is g 2.21 x 1020
Anuta_ua [19.1K]2 years ago
3 0
That is not right it is something to do with 21 or 20 but there more than one answer 
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Which expression is equivalent to t+4+3-2
FrozenT [24]

Answer:

t+5

Step-by-step explanation:

We can combine like terms, and get t+(4+3-2) to get t+5.

Hope this helped!

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2 years ago
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What is the product?(x − 3)(2x2 − 5x + 1)
slavikrds [6]
2x^3-11x^2+16x-3

the answew is above^^^^^^^^^^^^^
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Shapes?<br> what shape is this? plz help
son4ous [18]

Answer:

quadrilateral

Step-by-step explanation:

6 0
2 years ago
Luna into a rifle for a new pair of running shoes. She purchased 20 tickets and she told that she had 20% chance of winning. How
nikitadnepr [17]

Answer:

4 tickets were sold

Step-by-step explanation:if you have 100 of anything. 5 sets of 20=100


8 0
2 years ago
Read 2 more answers
1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.
xxTIMURxx [149]

First, rewrite the equation so that <em>y</em> is a function of <em>x</em> :

x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}

(If you were to plot the actual curve, you would have both y=x^{2/3} and y=-x^{2/3}, but one curve is a reflection of the other, so the arc length for 1 ≤ <em>x</em> ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx

We have

y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}

Then in the integral,

\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx

Substitute

u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx

This transforms the integral to

\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du

and computing it is trivial:

\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)

We can simplify this further to

\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}

7 0
3 years ago
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