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timama [110]
3 years ago
15

find a model for simple harmonic motion if the position at t = 0 is 6, the amplitude is 6 centimeters, and the period is 4 secon

ds
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
4 0

Answer:

y = 6cos(π/2)t

Step-by-step explanation:

Given in the question that,

in a simple harmonic motion in which

at t=0 the amplitude is 6 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at t=0 is 0.  

And,

the period is given as 4 sec

We know that model equation of simple harmonic motion is

<h3>y = a. cosb(t + c) + d</h3>

here,

a is amplitude

c is Horizontal shift or phase shift

d is Vertical shift

<h3>Step1</h3><h3>Find b</h3>

Period = 2 π / b

4 = 2π / b

b = 2π/4

b = 1π/2

<h3>Step2</h3><h3>Find shifts</h3>

Horizontal and vertical shifts are 0.

So, c = 0 and d = 0

<h3>Step3</h3><h3>Plug those values in the above in the equation</h3>

y = 6cos π/2 (t + 0) + 0

y = 6cos(π/2)t

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Answer:

We have the following equation: y = 36 - x. And we need to find which of the following points belong to the graph:

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If any of the points belong to the equation, then the equality will be met.

Then:

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