From the given function modeling the height of the ball:
f(x)=-0.2x^2+1.4x+7
A] The maximum height of the ball will be given by:
At max height f'(x)=0
from f(x),
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
thus the maximum height would be:
f(3.5)=-0.2(3.5)^2+1.4(3.5)+7
f(3.5)=9.45 ft
b]
How far from where the ball was thrown did this occur:
from (a), we see that at maximum height f'(x)=0
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
This implies that it occurred 3.5 ft from where the ball was thrown.
c] How far does the ball travel horizontally?
f(x)=-0.2x^2+1.4x+7
evaluationg the expression when f(x)=0 we get:
0=-0.2x^2+1.4x+7
Using quadratic equation formula:
x=-3.37386 or x=10.3739
We leave out the negative and take the positive answer. Hence the answer 10.3739 ft horizontally.
Https://coolconversion.com/geometry/circle/area/What-is-the-area-of-a-circle-with-_radius-_1_cm_%3F
This website might help
See, please, the offered decision, note, that 2x^2yxy^2 is as <span>2x^2y+xy^2.</span>
Answer:
x
=
2
,
y
=
3
Step-by-step explanation:
this is equation form if this what you were talking about :3
Answer:
4
Step-by-step explanation:
its like you have 2 fishes and you get two more
